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3 years ago

Does the reaction above satisfy the law of conservation of matter? Use details to support your work.

Physics

1 answer:

Leona [35]3 years ago

6 0

Answer:

No, the amount of matter of the reactants is not equal to the amount of matter of the products.

Explanation:

According to the conservation of matter the amount of matter of the reactants is equal to the amount of matter of the products. The given reaction is

$2H_2O_2=H_2+O_2$

In the reactant side there are $2\times 2=4$ molecules of hydrogen and $2\times 2=4$ molecules of oxygen.

In the product side there are 2 molecules of both hydgrogen and oxygen. So the reaction does not satisfy the law of conservation of mass.

The balanced reaction would be

$2H_2O_2=2H_2+2O_2$ .

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Which of these is the most likely prediction that the meteorologist would make about the weather? There is a possibility of

riadik2000 [5.3K]

Answer:

B. Dust storm

Explanation:

A meteorologist would predict dust storm most likely. Before dust storm the air condition and air pressure reduces in the particular area which indicate towards a dust storm. As pressure of a region reduces the air of the neighboring area try to maintain that pressure and rush towards low pressure area and causes dust storm.

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3 years ago

f1=30Nandf2=10Nact on amass of 2kg if the cofficient of friction between the mass and the horizontal surface is 0.2 what is the

Alexus [3.1K]

The mass is moving with an acceleration of 13.299 m/s².

<h3>What is the straight forward meaning of acceleration?</h3>

The rate at which an object's velocity with respect to time changes is referred to as acceleration in mechanics. They are vector quantities, accelerations.

According to therefore mentioned statement,

the direction of the net force applied on an object determines its acceleration;

according to mentioned data;

F₁=30N

F₂=10N

Net force on object;

F=F₁+F₂

F=F₁y+F₂Cos30°(-x)+F₂ Sinx(-y)

F=3y+10×(√3/2)(-x)+10×(1/2)(-y)

F=ma

ma=-5√3/2(x)+25y

2a=-5√3x/2+25y

a=-5√3x+25y

magnitude(a)=√(-5√3/2)²+(25/2)²

(a) =13.299m/s²

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2 years ago

Motor oil, with a viscosity of 0.25 N ∙ s/m2, is flowing through a tube that has a radius of 3.0 mm and is 1.0 m long. The drop

Alex73 [517]

Answer:

The average speed of the oil is 1 m/s.

Explanation:

Given that,

Viscosity $\eta= 0.25 N-s/m^2$

Radius r = 3.0 mm

Length = 1.0 m

Pressure = 200 kPa

We need to calculate the average speed of the oil

Using formula of pressure

$\Delta P=\dfrac{8\pi\eta\rho v}{A}$

$v=\dfrac{A\times\Delta P}{8\pi\eta\rho}$

Where, A = area

$\rho$ = density of oil

$\eta$ = viscosity

Put the value into the formula

$v=\dfrac{\pi\times(3.0\times10^{-3})^2\times200\times10^{3}}{8\pi\times0.25\times0.9}$

$v=1\ m/s$

Hence, The average speed of the oil is 1 m/s.

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4 years ago

Solenoid is wound with 2000 turns per meter when the current is 5.2 a, what is the magnetic field within the solenoid?

Drupady [299]

The magnetic field within the solenoid is 0.013T

<h3>What is Solenoid ?</h3>

An electromagnet known as a solenoid creates a regulated magnetic field using a helical coil of wire whose length is significantly higher than its diameter. When an electric current is sent through the coil, it may create a consistent magnetic field inside a defined region of space.

A solenoid operates by creating an electromagnetic field surrounding an armature, which is a moving core. The electromagnetic field causes the armature to move, and when it does, it opens and closes valves or switches, converting electrical energy into mechanical motion and force.

The magnetic field within the solenoid can be calculated by the expression given below.

Write the expression for magnetic field within the solenoid.

B = u₀nI

B = 4π * 10⁻⁷ * 2000 * 5.2

= 0.013 T

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1 year ago

A point charge is placed at the center of a spherical Gaussian surface. The electricflux ΦEischangedif(a) a second point charge

Simora [160]

Answer:

(b) the point charge is moved outside the sphere

Explanation:

Gauss' Law states that the electric flux of a closed surface is equal to the enclosed charge divided by permittivity of the medium.

$\int\vec{E}d\vec{a} = \frac{Q_{enc}}{\epsilon_0}$

According to this law, any charge outside the surface has no effect at all. Therefore (a) is not correct.

If the point charge is moved off the center, the points on the surface close to the charge will have higher flux and the points further away from the charge will have lesser flux. But as a result, the total flux will not change, because the enclosed charge is the same.

Therefore, (c) and (d) is not correct, because the enclosed charge is unchanged.

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3 years ago