Julie used 1-centimeter cubes to make the figure below.

What is the approximate circumference of Circle C? Use pi star times text end text ≈ 3.14. Record your answer to the nearest h

Stels [109]

Circumference of a circle is found with the equation

C = 2 × pi × r

where r is the radius. So for your problem...

C = 2 × 3.14 × 4
C = 25.12 meters

7 0

3 years ago

F(x) = -5x g(x) = 8x^2 - 5x - 9 find (f•g)(x)

Stells [14]

Answer:

B

Step-by-step explanation:

You are making composite functions, since all the answers provided dont fit, I only suggest to clearify that the lone term in the B option, is actually 45x and not 45.

If this is the case, composite functions means that you eval the expresion g(x) in every x variable found in f(x).

Using this, it gives you that f(g(x))= $-40x^{2} +25x+45$

6 0

3 years ago

The swimming pool at lifetime city health and fitness club measures 20 meters in length and 15 meters in width wat is the are of

8_murik_8 [283]

20*15 is 300 meters which is the area

8 0

2 years ago

Read 2 more answers

Math Help Please explain the questions How long will it take for the balance of an account to double if the savings account earn

Scorpion4ik [409]

(See attached formula)
Years = log (total / principal) / n*log(1 + rate/n) where n = compounding periods per year
Years = log (total / principal) / n*log(1 + rate/n)
Rate of .75% = .0625 per month
We'll say we want total = 200 and principal = 100
Years = log (200 / 100) / 12*log(1 + rate/n)
Years = log (2) / 12 * log (1 + .0625/12)
Years = 0.3010299957 / 12 * 0.0022560803 
Years = 0.3010299957 / 0.0270729635 
Years = 11.1192110871 
I don't think that's right
The interest rate is REALLY low. (Less than 1%)
Rate = .75 and .0075 when in a formula
Years = log (2) / 12 * log (1 + .0075/12)
Years = log (2) / 12 * log( 1.000625)
Years = 0.3010299957 / 12 * 0.0002713493 
Years = 0.3010299957 / 0.0032561912 
Years = 92.4485010892
THAT seems a more likely answer with such a low interest rate.

5 0

2 years ago

a regular rectangular pyramid has a base and lateral faces that are congruent equilateral triangles. it has a lateral surface ar

Margarita [4]

A pyramid is regular if its base is a regular polygon, that is a polygon with equal sides and angle measures.
(and the lateral edges of the pyramid are also equal to each other)

Thus a regular rectangular pyramid is a regular pyramid with a square base, of side length say x.

The lateral faces are equilateral triangles of side length x.

The lateral surface area is 72 cm^2, thus the area of one face is 72/4=36/2=18 cm^2.

now we need to find x. Consider the picture attached, showing one lateral face of the pyramid.

by the Pythagorean theorem:

$h= \sqrt{ x^{2} - (x/2)^{2}}= \sqrt{ x^{2}- x^{2}/4}= \sqrt{3x^2/4}= \frac{ \sqrt{3} }{2}x$

thus,

$Area_{triangle}= \frac{1}{2}\cdot base \cdot height\\\\18= \frac{1}{2}\cdot x \cdot \frac{ \sqrt{3} }{2}x\\\\ \frac{18 \cdot 4}{ \sqrt{3}}=x^2$

thus:

$x^2 =\frac{18 \cdot 4}{ \sqrt{3}}= \frac{18 \cdot 4 \cdot\ \sqrt{3} }{3}=24 \sqrt{3}$ (cm^2)

but $x^{2}$ is exactly the base area, since the base is a square of sidelength = x cm.

So, the total surface area = base area + lateral area = $24 \sqrt{3}+72$ cm^2

Answer: $24 \sqrt{3}+72$ cm^2

4 0

2 years ago