Answer:The computer writes electron configurations in the form, for Co for example, [Ar]3d(7)4s(2), which we would write [Ar]3d74s2
NOTE: Write electron configurations as they appear in the periodic table in the front of you text put 4f before 5d
Explanation:
Answer:
pH of the H⁺(aq) is 0
Explanation:
It is possible to know the concentration of a HCl(aq) solution by titration with a solution of NaOH(aq) with known concentration. The reaction is:
HCl(aq) + NaOH(aq) → H₂O(l) + NaCl(aq)
The added moles of NaOH are equal to moles of HCl and as you know volume of HCl added you will obtain concentration of HCl.
Now, a solution of H⁺(aq) with a concentration 10 times greater than original NaOH(aq) solution -0.100M-, has a concentration of 1.00M H⁺(aq), the pH of this solution is:
pH = -log (1.00M H⁺(aq) = 0
That means <em>pH of the H⁺(aq) is 0</em>
Given:
K = 0.71 = Kp
The reaction of sulphur with oxygen is
S(s) + O2(g) ---> SO2(g)
initial Pressure 6.90 0
Change -x +x
Equilibrium 6.90-x x
Kp = pSO2 / pO2 = 0.71 = x / (6.90-x)
4.899 - 0.71x = x
4.899 = 1.71x
x = 2.86 atm = pressure of SO2 formed
temperature = 950 C = 950 + 273.15 K = 1223.15 K
Volume = 50 L
Let us calculate moles of SO2 formed using ideal gas equation as
PV = nRT
R = gas constant = 0.0821 L atm / mol K
putting other values
n = PV / RT = 2.86 X 50 / 1223.15 X 0.0821 = 1.42 moles
Moles of Sulphur required = 1.42 moles
Mass of sulphur required or consumed = moles X atomic mass of sulphur
mass of S = 1.42 X 32 = 45.57 grams or 0.04557 Kg of sulphur
The bowl has more volume, the bearing has more volume. The mass is bigger for the bearing because it is heavier than the bowl. It is made of metal and the weight of it is greater than the bowl.(the body shape).
