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mart [117]
3 years ago
15

Molasses is a by-product of the refining of sugar cane. The specific composition of molasses varies depending upon the source of

the sugar cane. Which one of the following is the best classification of molasses?
A. mixture
B. pure substance
C. compound
D. element
Chemistry
1 answer:
marysya [2.9K]3 years ago
3 0

Answer:

A. mixture

Explanation:

Molasses is a mixture as such, it cannot have a chemical formula.

Molasses is made up of 75% carbohydrates, 22% water with 0% fat or protein. It is a good source of 20% or more of the Daily Value of vitamin B6 and other important dietary found in molasses includes , calcium iron, magnesium potassium and manganese.

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igomit [66]

Answer:

B)3

Explanation:

I'm assuming the 2 is meant to be smaller. If it were a regular size 2 the answer would be 2 and that isn't an option

7 0
3 years ago
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Alona [7]
I think the answer is C.
8 0
3 years ago
Carbon, hydrogen and ethane each burn exothermically in an excess of air. AHⓇ =-393.7 kJ mol. C(s) + O2(g) → CO2(g) H2(g) + % O2
Salsk061 [2.6K]

<u>Answer:</u> The \Delta H^o_{rxn} for the reaction is 51.8 kJ.

<u>Explanation:</u>

Hess’s law of constant heat summation states that the amount of heat absorbed or evolved in a given chemical equation remains the same whether the process occurs in one step or several steps.

According to this law, the chemical equation is treated as ordinary algebraic expressions and can be added or subtracted to yield the required equation. This means that the enthalpy change of the overall reaction is equal to the sum of the enthalpy changes of the intermediate reactions.

The chemical equation for the reaction of carbon and water follows:

2C(s)+2H_2(g)\rightarrow C_2H_4(g) \Delta H^o_{rxn}=?

The intermediate balanced chemical reaction are:

(1) C(s)+O_2(g)\rightarrow CO_2(g)    \Delta H_1=-393.7kJ    ( × 2)

(2) H_2+\frac{1}{2}O_2(g)\rightarrow H_2O(l)    \Delta H_2=-285.9kJ     ( × 2)

(3) 2C_2H_4(s)+2O_2(g)\rightarrow 2CO_2(g)+2H_2O(l)    \Delta H_3=-1411kJ

The expression for enthalpy of the reaction follows:

\Delta H^o_{rxn}=[2\times \Delta H_1]+[2\times \Delta H_2]+[1\times (-\Delta H_3)]

Putting values in above equation, we get:

\Delta H^o_{rxn}=[(2\times (-393.7))+(2\times (-285.9))+(1\times -(-1411))]=51.8kJ

Hence, the \Delta H^o_{rxn} for the reaction is 51.8 kJ.

6 0
3 years ago
A sample of sugar (C12H22O11) contains
Oduvanchick [21]

Answer: 0.25 mol

Explanation:

Use the formula n=N/NA

n= number of mols

N =  number of particles

Nᵃ = Avogadros constant = 6.02 x

So, n=

The 10 to the power of 23 cancels out and you are left with 1.505/6.02, which is approximately 1/4. This is the same as 0.25 mol.

Hope this helped :)

5 0
3 years ago
Is a CAS number a physical or chemical property
katrin [286]
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Hope that helps
5 0
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