If the probability of observing at least one car on a highway during any 20-minute time interval is 609/625, then the probability of observing at least one car during any 5-minute time interval is 609/2500
Given The probability of observing at least one car on a highway during any 20 minute time interval is 609/625.
We have to find the probability of observing at least one car during any 5 minute time interval.
Probability is the likeliness of happening an event among all the events possible. It is calculated as number/ total number. Its value lies between 0 and 1.
Probability during 20 minutes interval=609/625
Probability during 1 minute interval=609/625*20
=609/12500
Probability during 5 minute interval=(609/12500)*5
=609/2500
Hence the probability of observing at least one car during any 5 minute time interval is 609/2500.
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Answer:
Since opposite sides of parallelogram are equal therefore
9r-6=8r+3
r=9
EF=4r+19{opposite sides of parallelogram are equal}
=4×9+19
36+19
=55
Here is you answer.
Step-by-step explanation:
1, -1 !!! i hope this helps (also download mathpapa :D )
Plug in each of the answer choices into the 'y=' button and check each table. If all of the ordered pairs are shown in one equation table, then that is your representing function.
