3(2x^3+3y^2) (2x^3 -3y^2)
Answer:
26.4 km/hr
Step-by-step explanation:
Sofia and Diego drive to work.
For Sofia
We convert miles to km
Sofia drives 72 miles in 1.5 hours.
1 mile = 1.6 km
72 miles = x
x = 72 × 1.6 km
x = 115.2 km
We find the speed in km/hr
Speed = Distance /Time
= 115.2km/1.5 hours
= 76.8 km/hr
For Diego
Diego drives 126 km in 2 hour 30 min.
Speed = Distance/Time
Time = 2 hour 30 min = 2.5 hours
Speed = 126km/2.5 hours
= 50.4 km/hr
The difference between their average speeds in km/h is calculated as:
76.8 km/hr - 50.4 km/hr
= 26.4 km/hr
It will increase $7473. The new model will be $60473. Please don't ask me how I got it. I just figured it out in my head. I can't really explain how I got it.
Step-by-step explanation:
<h2><u>➤ </u><u>Solution :-</u></h2><h2>a)</h2>
Given monomials are 21 xy³ and 24x²y²
21 xy³ = 3×7×x×y×y×y
24x²y² = 3×8×x×x×y×y
HCF of 21xy³ and 24x²y²
=> 3×x×y×y
=> 3xy²
HCF of 21xy³ and 24x²y² = 3xy²
<h2>b)</h2>
Given monomials are 18 ab and 36abc
18 ab = 18×a×b
36abc = 2×18×a×b×c
HCF of 18 ab and 36abc
=> 18×a×b
=> 18ab
HCF of 18 ab and 36abc = 18ab
<h2>c)</h2>
Given monomials are 4p³q²r , -12pqr² and 16p²q²r²
4p³q²r = 4×p×p×p×q×q×r
-12pqr² = -3×4×p×q×r×r
16p²q²r² = 4×4×p×p×q×q×r×r
HCF of 4p³q²r , -12pqr² and 16p²q²r²
=> 4×p×q×r
=> 4pqr
HCF of 4p³q²r , -12pqr² and 16p²q²r² = 4pqr
<h2><u>Used Concept :-</u></h2>
→ The HCF of two or more numbers is the highest Common factor
→ The product of least common factors is the HCF of the numbers
