Using the following given values:
Object 1:
Mass = M1 = 2 kg
Velocity before collision = Vb1 = 20 m/s
Velocity after collision = Va1 = -5 m/s
Object 2:
Mass = M2 = 3 kg
Velocity before collision = Vb2 = -10 m/s
Velocity after collision = Va2 = ? m/s<span>
</span>
Obtaining Va2 via law of conservation of momentum:
total momentum after collision = total momentum before collision
M1 * Va1 + M2 * Va2 = M1 * Vb1 + M2 * Vb2
2*-5 + 3Va2 = 2*20 + 3*-10
Va2 = 6.67
Total kinetic energy before collision:
KE1 = (1/2)*M1*Vb1^2 + (1/2)*M2*Vb2^2
<span>KE1 = (1/2)*2*(20)^2 + (1/2)*3*(-10)^2
KE1 = 550 J
</span>Total kinetic energy after collision:
KE2 = (1/2)*M1*Va1^2 + (1/2)*M2*Va2^2
<span>KE2 = (1/2)*2*(-5)^2 + (1/2)*3*(6.67)^2
KE2 = 91.73 J
</span>
Total kinetic energy lost:
Energy lost = KE1 - KE2 = 550 - 91.73 = 458.27 J
Two current processes that is used in ensuring that there is enough clean water is maintaining environmental sanitation in communities in which will help promote cleanliness and orderliness and another thing, having people to be educated with cleanliness and proper waste disposal as this will contribute to making the water clean and maintain it that way.
Answer:
The answer is
<h2>40 J</h2>
Explanation:
The kinetic energy of an object given it's mass and velocity can be found by using the formula
where
m is the mass
v is the velocity
From the question
m = 5 kg
v = 4 m/s
The kinetic energy is
We have the final answer as
<h3>40 J</h3>
Hope this helps you
Water is a really good conductor of sound so I would have to say that it would be to send the message underwater because a more dense medium produces a louder sound
Gravity, and Normal. Check the comments for why Applied isn't one.
