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Anna71 [15]
3 years ago
12

Which of the following best describes a property of water?

Physics
2 answers:
Snezhnost [94]3 years ago
5 0

Answer: C. Remaining liquid over a wide temperature range

Explanation: Water has a high specific heat i.e it requires a large amount of heat to raise the temperature of 1 gram of water through 1^0C. This is because the molecules of water are associated through strong hydrogen bonds.

It is also an universal solvent as it can dissolve most of the substances in it due to its high dielectric constant.

The freezing point of water is  0^0C, that is liquid water converts to solid form at 0^0C and the boiling point of water is  100^0C, that is liquid water converts to gaseous form at 100^0C. Thus it can remain in liquid form over the temperature range of  0^0C to 100^0C.

Water has a high surface tension as the molecules of water are held together by strong hydrogen bonds.

stiks02 [169]3 years ago
3 0

Correct answer is option C.

Remaining liquid over a wide temperature range  

Other options are invalid.

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How fast must a 1000 kg car be moving to have a kinetic energy of 2.0×10^5j​
ankoles [38]

Answer:

E=0.5 m v^2

2*10^-5 = 0.5 1000*v^2

4*10^-5=1000v^2

4*10^-8=v^2

2*10^-4 =v

7 0
3 years ago
A box is pushed 40 m by a mover. The amount of work done was 2,240 j. How much force was exerted on the box
Georgia [21]

The force exerted on the box is 56 N

Explanation:

The work done by a force on an object is given by

W=Fd cos \theta

where

F is the magnitude of the force

d is the displacement of the object

\theta is the angle between the direction of the force and of the displacement

For the box in this problem, we have:

W = 2240 J is the work done

d = 40 m is the displacement of the box

Assuming that the  force is parallel to the displacement, \theta=0

Solving the equation for F, we find the force exerted on the box:

F=\frac{W}{d cos \theta}=\frac{2240}{(40)(cos 0)}=56 N

Learn more about work:

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3 0
3 years ago
A car slows down from 80 km/h to 60 km/h in 2 seconds.
Andreyy89

Answer:

please mark brainlist

Explanation:

Initial speed   u=80 km/h=80×185=22.22 m/s

Final speed    v=60 km/h=60×185=16.67 m/s

Using   v=u+at

Or   16.67=22.22+α×5

⟹ a=−1.1 m/s2

6 0
3 years ago
a cylindrical jar is 10cm long and has a cross sectional area of 36cm. if it is completely filled with a fluid of relative densi
ki77a [65]

Answer:

The mass of the fluid is 72 g.

Explanation:

The following data were obtained from the question:

Height (h) = 10 cm

Area of cross section (A) = 36cm²

Relative density = 0.2

Mass =..?

Next, we shall determine the volume of the cylinder. This can be achieved by doing the following:

Volume = Area x Height

Volume = 36 x 10

Volume = 360 cm³

Next, we shall determine the density of the liquid.

This can be obtained as follow:

Relative density = density of substance/density of water.

Relative density = 0.2

Density of water = 1 g/cm³

Density of fluid =...?

Relative density = density of substance/density of water.

0.2 = density of fluid / 1 g/cm³

Cross multiply

Density of fluid = 0.2 x 1 g/cm³

Density of fluid = 0.2 g/cm³

Finally, we shall determine the mass of fluid as follow:

Volume = 360 cm³

Density of fluid = 0.2 g/cm³

Mass of fluid =...?

Density = mass /volume.

0.2 g/cm³ = mass of fluid /360 cm³

Cross multiply

Mass of fluid = 0.2 g/cm³ x 360 cm³

Mass of fluid = 72 g

Therefore, the mass of the fluid in the jar is 72 g.

6 0
3 years ago
A boy and a girl are on a spinning merry-go-round. The boy is at a radial distance of 1.2 m from the central axis; the girl is a
Licemer1 [7]

Answer:

E) True. The girl has a larger tangential acceleration than the boy.

Explanation:

In this exercise they do not ask us to say which statement is correct, for this we propose the solution to the problem.

Angular and linear quantities are related

          v = w r

          a = α r

the boy's radius is r₁ = 1.2m the girl's radius is r₂ = 1.8m

as the merry-go-round rotates at a constant angular velocity this is the same for both, but the tangential velocity is different

          v₁ = w 1,2 (boy)

          v₂ = w 1.8 (girl)

whereby

          v₂> v₁

reviewing the claims we have

          a₁ = α 1,2

          a₂ = α 1.8

          a₂> a₁

A) False. Tangential velocity is different from zero

B) False angular acceleration is the same for both

C) False. It is the opposite, according to the previous analysis

D) False. Angular acceleration is equal

E) True. You agree with the analysis above,

8 0
3 years ago
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