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3 years ago

Which of the following best describes a property of water?

Physics

2 answers:

Snezhnost [94]3 years ago

5 0

Answer: C. Remaining liquid over a wide temperature range

Explanation: Water has a high specific heat i.e it requires a large amount of heat to raise the temperature of 1 gram of water through $1^0C$ . This is because the molecules of water are associated through strong hydrogen bonds.

It is also an universal solvent as it can dissolve most of the substances in it due to its high dielectric constant.

The freezing point of water is $0^0C$ , that is liquid water converts to solid form at $0^0C$ and the boiling point of water is $100^0C$ , that is liquid water converts to gaseous form at $100^0C$ . Thus it can remain in liquid form over the temperature range of $0^0C$ to $100^0C.$

Water has a high surface tension as the molecules of water are held together by strong hydrogen bonds.

stiks02 [169]3 years ago

3 0

Correct answer is option C.

Remaining liquid over a wide temperature range

Other options are invalid.

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Blizzard [7]

Answer A

Explanation: because u need to make sure you know the difference between a need and a want

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3 years ago

A sled plus passenger with total mass m = 53.1 kg is pulled a distance d = 25.3 m across a horizontal, snow-packed surface for w

Alex Ar [27]

Answer:

Explanation:

Force of friction

F = μ mg

μ is coefficient of friction , m is mass and g is acceleration due to gravity .

If f be the force applied to pull the sled , the horizontal component of force should be equal to frictional force

The vertical component of applied force will reduce the normal force or reaction force from the ground

Reaction force R = mg - f sin28.3

frictional force = μ R where μ is coefficient of friction

frictional force = μ x (mg - f sin28.3 )

This force should be equal to horizontal component of f

μ x (mg - f sin28.3 ) = f cos 28.3

μ x mg = f μsin28.3 + f cos 28.3

f = μ x mg / (μsin28.3 + cos 28.3 )

a )

work done by pulling force = force x displacement

f cos28.3 x d

μ x mg d cos28.3 / (μsin28.3 + cos 28.3 )

b ) Putting the given values

= .155 x 53.1 x 9.8 x 25.3 cos28.3 / ( .155 x sin28.3 + cos 28.3 )

= 1796.76 / (.073 + .88 )

= 1885.37 J

c )

Work done by frictional force

= frictional force x displacement

= - μ x (mg - f sin28.3 ) x d

= - μ x mgd + f μsin28.3 x d

= - μ x mgd + μsin28.3 x d x μ x mg / (μsin28.3 + cos 28.3 )

d )

Putting the values in the equation above

- .155 x 53.1 x 9.8 x 25.3 +

.155 x .474 x 25.3 x .155 x 53.1 x 9.8 /( .155 x .474 + .88)

= -2040.67 + 149.92 / .95347

= -2040.67 + 157.23

= -1883.44 J .

6 0

3 years ago

If a wave vibrates up and down twice each second and travels a distance of 20 m each second and travels a distance of 20 m each

ivolga24 [154]

Answer:

Frequency is 0.5 Hz and the wave speed is 10 m/s.

Explanation:

As we know that frequency is defined as the how many times the no of cycles repeat in one second so if the wave is vibrating up and down twice during 1 second then the frequency in 1 second is

$f=\frac{1}{2} hz\\F=0.5hz$