To give solution to the exercise we must use the concepts of Torque, Vector magnitude and vector direction of the forces.
For the given problem we have to
In this way the torque acting on the particle as a function of distance and time is,
The net torque acting on the particle is
PART B) The direction of the torque is given by,
Therefore the torque direction is 48.04° below the x axis.
Answer: C
Explanation:
A bird flying in the air is 3D motion as the bird move up, down, right, left all the possible direction. A leaf falling from a tree is also a 3D motion because a leaf never fall in absolute vertical manner. A lady bug crawling on a soccer ball also 3D. If lady bug crawling on a plane like floor then it is 2D but now lady bug crawling on soccer ball which is in spherical shape so it is also 3D motion. Only train travelling along a track is 2D because train cannot move up and down and the track of train is in a plane. So it is 2D motion.
Answer:
Q = C M T where C is the specific, M the mass, T the temperature change
Note 1 cal = 4.19 Joules
1562.75 J / (4.19 J/cal) = 378 cal
C = Q / (M * T) = 378 cal / (25.35 g * 155 deg C)
C = .096 cal / g deg C
The potential difference across the capacitor is 5 × 10∧4 volts and the energy stored in it is 1. 25 Joules
<h3>
What is the energy in a capacitor?</h3>
The energy stored in a capacitor is an electrostatic potential energy.
It is related to the charge(Q) and voltage (V) between the capacitor plates.
It is represented as 'U'.
<h3>
How to determine the potential difference</h3>
Formula:
Potential difference, V is the ratio of the charge to the capacitance of a capacitor.
It is calculated using:
V = Q ÷ C
Where Q = charge 5 × 10∧-5C and C = capacitance 10∧-9
Substitute the values into the equation
Potential difference, V = 5 × 10∧-5 ÷ 10∧-9 = 5 × 10∧4 volts
<h3>
How to determine the energy stored</h3>
Formula:
Energy, U = 1 ÷ 2 (QV)
Where Q= charge and V = potential difference across the capacitor
Energy, U = 1 ÷ 2 ( 5 × 10∧-5 × 5 × 10∧4)
= 0.5 × 25 × 10∧-1
= 0.5 × 2.5
= 1. 25 Joules
Therefore, the potential difference across the capacitor is 5 × 10∧4 volts and the energy stored in it is 1. 25 Joules
Learn more about capacitance here:
brainly.com/question/14883923
#SPJ1
