Answer:
0.80865 Hz
1.23662 seconds
Explanation:
g = Acceleration due to gravity = 9.81 m/s²
l = Length of arm = 0.57 m
Length of simple pendulum is given by

The frequency is given by

The frequency is 0.80865 Hz
The time period is given by

The time period is 1.23662 seconds
 
        
             
        
        
        
Answer:
The maximum velocity is 1.58 m/s. 
Explanation:
A spring pendulum with stiffness k = 100N/m is attached to an object of mass m = 0.1kg, pulls the object out of the equilibrium position by a distance of 5cm, and then lets go of the hand for the oscillating object. Calculate the achievable vmax. 
Spring constant, K = 100 N/m 
mass, m = 0.1 kg 
Amplitude, A = 5 cm = 0.05 m 
Let the angular frequency is w. 

The maximum velocity is 

 
        
             
        
        
        
Th answer is A sorry if this isn’t what your looking for
        
                    
             
        
        
        
Answer:
 12.7m/s 
Explanation:
Given parameters: 
Mass of diver  = 77kg 
Height of jump  = 8.18m 
Unknown: 
Final velocity  = ? 
Solution: 
To solve this problem, we apply the motion equation below: 
              v²   = u²  + 2gH 
v is the final velocity 
u is the initial velocity 
g is the acceleration due to gravity 
H is the height
  Now insert the parameters and solve; 
        v² = 0²  +  2 x 9.8 x 8.18 
      v  = 12.7m/s