Answer:
The vulture loses 6.1 m height
Explanation:
Please see the attached figure.
The horizontal distance and the loss of height form a 90º triangle.
The loss of height is the side opposite the given angle (3.5º) and the 100 m horizontal distance is adjacent the angle.
Then, using trigonometric rules:
(1) sin 3.5º = h / hyp
(2) cos 3.5º = distance / hyp
where
h = height lost during the flight.
hyp = hypotenuse of the triangle
Using (2) we can calculate the hypotenuse:
cos 3.5º = 100 m / hyp
hyp = 100 m / cos 3.5º = 100.2 m
with the hypotenuse we can now calculate the loss of height using (1):
sin 3.5º = h / hyp
sin 3.5º = h / 100.2 m
sin 3.5º * 100.2 m = h
<u>h = 6.1 m</u>
( very modest drop in height indeed!)
Answer:
13.18m/s²
Explanation:
According to Newton's second law of motion
Force = Mass * acceleration
Given
Mass = 11kg
Force = 145N
Required
acceleration
From the formula
Acceleration = Force/Mass
Acceleration = 145/11
Acceleration = 13.18m/s²
Hence the initial acceleration of the object is 13.18m/s²
Answer:
Explanation:
18 kW = 18000 J /s
60% of 18kW = 10800 J/s
Latent heat of evaporation of water
= 2260 x 10³ J / kg
kg of water being evaporated per second
= 10800 / 2260 x 10³ kg /s
= 4.7787 x 10⁻³ kg / s
= 4.78 gm / s .
Just so you know people aren’t replying because the bar graph isn’t show :/
Answer:
Option b
Solution:
As per the question:
Speed of the mouse, v = 1.3 m/s
Speed of the cat, v' = 2.5 m/s
Angle, 
Now,
To calculate the distance between the mouse and the cat:
The distance that the cat moved is given by:
The position of the cat and the mouse can be given by:
x' = 0.67 t (1)
The initial speed of the cat ahead of the mouse:
u = 
When the time is 0.5t, the speed of the cat is 0, thus:
Substituting the value of t in eqn (1):
x' = 0.67(0.314) = 0.210 m
Thus the distance comes out to be 0.210 m
