Given:
v = 50.0 m/s, the launch velocity
θ = 36.9°, the launch angle above the horizontal
Assume g = 9.8 m/s² and ignore air resistance.
The vertical component of the launch velocity is
Vy = (50 m/s)*sin(50°) = 30.02 m/s
The time, t, to reach maximum height is given by
(30.02 m/s) - (9.8 m/s²)*(t s) = 0
t = 3.0634 s
The time fo flight is 2*t = 6.1268 s
The horizontal velocity is
u = (50 m/s)cos(36.9°) = 39.9842 m/s
The horizontal distance traveled at time t is given in the table below.
Answer:
t, s x, m
------ --------
0 0
1 39.98
2 79.79
3 112.68
4 159.58
5 199.47
6 239.37
We need to charge a metal sphere positively without touching it. This can be achieved using electrostatic induction.
Answer:

Part 1

Part 2

Explanation:
Given that
Diameter,d=1 μm
Length ,l=2 μm
As we know that volume of cylinder given as



Surface area,A
A=π d l


Part 1

Part 2

Answer:
... If your arrows are too lightly or heavily spined for your bow, the “archer's paradox” resulting in poor arrow flight and loss of accuracy.