I think so, <span> how much of all chemistry is to do with numbers? A lot! So being good at mathematics makes a huge aspect of chemistry so much easier but if you aren't mathematical then you can work at it and become reasonably proficient at it.</span>
<u>Answer:</u> The amount of carbon dioxide formed in the reaction is 47.48 grams
<u>Explanation:</u>
For the given chemical equation:

To calculate the actual yield of carbon dioxide, we use the equation:

Percentage yield of carbon dioxide = 83 %
Theoretical yield of carbon dioxide = 1.30 moles
Putting values in above equation, we get:

To calculate the number of moles, we use the equation:

Molar mass of carbon dioxide = 44 g/mol
Moles of carbon dioxide = 1.079 moles
Putting values in above equation, we get:

Hence, the amount of carbon dioxide formed in the reaction is 47.48 grams
As we know that
<span>V1/T1 = V2/T2
V1 = 9.10 L
T1 = 471 K
V2 = 2.50 L
T2 = 2.5 x 471 / 9.10 = 129.3 K
T2 = 129.3 - 273 =
-143.6 deg Celsiu
hope it helps</span>