B. a sugar crystal
Because sugar comes from plants, it is classified as an organic compound, not a mineral.
Mass of CO₂ = 33 g
<h3>Further explanation </h3>
Complete combustion of Hydrocarbons with Oxygen will be obtained by CO₂ and H₂O compounds.
If O₂ is insufficient there will be incomplete combustion produced by CO and H and O
Reaction
CH₄ + 2O₂⇒CO₂ + 2H₂O
mol CH₄ :
mol O₂ :
A method that can be used to find limiting reactants is to divide the number of moles of known substances by their respective coefficients
Because O₂ ratio smaller then O₂ becomes the limiting reactants
So mol CO₂ from limiting reactants
mol CO₂ :
mass CO₂ :
Answer:
Explanation:
Combustion reaction is given below,
C₂H₅OH(l) + 3O₂(g) ⇒ 2CO₂(g) + 3H₂O(g)
Provided that such a combustion has a normal enthalpy,
ΔH°rxn = -1270 kJ/mol
That would be 1 mol reacting to release of ethanol,
⇒ -1270 kJ of heat
Now,
0.383 Ethanol mol responds to release or unlock,
(c) Determine the final temperature of the air in the room after the combustion.
Given that :
specific heat c = 1.005 J/(g. °C)
m = 5.56 ×10⁴ g
Using the relation:
q = mcΔT
- 486.34 = 5.56 ×10⁴ × 1.005 × ΔT
ΔT= (486.34 × 1000 )/5.56×10⁴ × 1.005
ΔT= 836.88 °C
ΔT= T₂ - T₁
T₂ = ΔT + T₁
T₂ = 836.88 °C + 21.7°C
T₂ = 858.58 °C
Therefore, the final temperature of the air in the room after combustion is 858.58 °C
A. Bacteria are stored in the lymph nodes
Answer:
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Explanation:
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