It is possible to dehydrate neutral and basic gases, amines, low-boiling alcohols, and ethers using calcium oxide, a basic drying agent. its chemical formula is CaO.
CaO cannot be substituted with sulfuric acid. Because the salt ammonium sulfate is created when sulphuric acid and ammonia combine, this is the case. Calcium oxide is a solid that is odorless, white, gray-white, and appears as hard lumps. powerful skin, eye, and mucous membrane irritant. used in fertilizers and pesticides. The group of calcium oxides with a 1:1 ratio of calcium to oxygen includes calcium oxide. It functions as fertilizer.
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B:Oxygen and silicon
Explanation:
Most minerals on the earth's surface contains oxygen and silicon. Silicon and oxygen are the most abundant elements we find in the rock minerals on the earth surface.
- Silicon and oxygen forms the SiO₄⁻ tetrahedron through which several minerals are formed.
- These minerals built on the network of the tetrahedron are referred to as silicates.
- Several silicate minerals are known:
- Quartz
- Feldspars
- Olivine
- Biotite
- Pyroxene
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Answer:
2.41065 grams
Explanation:
Here we have to apply molarity, particularly in reference to the equation molarity = moles of solute / volume. I would like to rewrite this formula, but with respect to the units - grams = moles / Liters,
We can use molarity to determine the number of moles. After doing so, we can determine the mass of the solute with respect to the formula moles = mass / molar mass. The molar mass of NaCl is 58.44 grams.
_______________________________________________________
275 mL = 0.275 L,
Number of Moles of NaCl = 0.150 * 0.275 = 0.04125 moles,
Mass = 0.04125 * 58.44 = 2.41065 grams,
Solution - Mass of NaCl = 2.41065 grams
<u><em>Hope that helps!</em></u>
Answer: The concentration of 
is 0.234 M
Explanation:
According to the neutralization law,
where,
= basicity = 2
= molarity of solution = ?
= volume of solution = 50.0 ml
= acidity of 
= 1
= molarity of solution = 0.375 M
= volume of solution = 62.5 ml
Putting in the values we get:
Therefore concentration of is 0.234 M
