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aliina [53]
3 years ago
5

Chemical reaction is the final part of the sentence​

Chemistry
1 answer:
Maslowich3 years ago
8 0

Answer:

b) 3A  + 2B   →   C

Explanation:

In given ratios of substances there are three mole of reactant A two moles of reactant B and one mole of product C are present.

A : B     3 : 2                          A : C     3 :  1             B : C        2  :  1

So from given information option b is correct.

3A  + 2B   →   C

Here in this equation three moles of A , two moles of B and one mole of C are present.

Other options are incorrect because,

a) 6A  + 6B   →   2C

In this chemical equation six moles of A six moles of B and two mole of C are present. So it is incorrect.

c) A + 2B →   3C

In this chemical equation one mole of A two mole of B and three moles of C are present. So it is incorrect.

d) A + B →   C

In this chemical equation one mole of A one mole of B and one mole of C are present. So it is incorrect.

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RideAnS [48]

Answer:

Sodium chloride is an ionic compound which makes it stronger and have a higher melting and boiling point. Candle wax is a covalent compound so it has a low melting point.

Explanation:

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Answer:

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3 years ago
Which of the following statements explains which trial has a lower concentration of the reactant? (5 points) Trial 1, because th
PIT_PIT [208]

Answer:

A)Trial 1 because the average rate of reaction is lower.

Explanation:

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5 0
3 years ago
Read 2 more answers
How many moles of oxygen are in 52.5 grams of oxygen gas?
adell [148]
An oxygen gas is a diatomic molecule which means that each molecule is composed of 2 atoms. Its symbol is O2. 

Each oxygen atom has a molar mass of 16 g/mol. The molar mass of oxygen gas is calculated below,
                         molar mass = 2 x (16 g/mol) = 32 g/mol

To determine the number of moles in 52.5 grams of oxygen, divide the given mass by the calculated molar mass.
 
                                 n = 52.5 grams / (32 gram/ mol)
                                     n = 1.64 moles

Thus, there are 1.64 moles of oxygen gas. 
3 0
3 years ago
Determine the specific heat ofmaterial if a 12g sample absorbed 48j as it was heated from 20-40
devlian [24]

Answer:

c =0.2 J/g.°C

Explanation:

Given data:

Specific heat of material = ?

Mass of sample = 12 g

Heat absorbed = 48 J

Initial temperature = 20°C

Final temperature = 40°C

Solution:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT =  40°C -20°C

ΔT =  20°C

48 J = 12 g×c×20°C

48 J =240 g.°C×c

c = 48 J/240 g.°C

c =0.2 J/g.°C

6 0
2 years ago
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