Question

7. A scientist studying a squid observes that the squid at rest

Answer 1

The average force on the squid during the ejection of 0.60 kg of water at a velocity of 15.0 m/s in 0.15 seconds is 60 N.              

We can calculate the average force with the average acceleration as follows:

$F = m\overline{a}$   (1)

Where:

• m: is the mass of water = 0.60 kg

• $\overline{a}$: is the average acceleration

The average acceleration is given by the change of velocity in an interval of time

$\overline{a} = \frac{v_{f} - v_{i}}{t_{f} - t_{i}}$   (2)

Where:

• $v_{i}$: is the initial velocity = 0 (the squid is at rest)

• $v_{f}$: is the final velocity = 15.0 m/s

• $t_{i}$: is the initial time = 0  

• $t_{f}$: is the final time = 0.15 s

Now we can find the average force after entering equation (2) into (1)

$F = m(\frac{v_{f} - v_{i}}{t_{f} - t_{i}}) = 0.60 kg(\frac{15.0 m/s - 0}{0.15 s}) = 60 N$  

Therefore, the average force on the squid during the propulsion is 60 N.

Find more about average force here:

• brainly.com/question/20902034

• brainly.com/question/12916904

I hope it helps you!