The reaction for the formation of MgO(s):
2 Mg (s) + O2(g) -à
2MgO(s) ΔH = -601.24
kJ/mol
<span>The enthalpy
information is taken from: http://webbook.nist.gov/cgi/inchi?ID=C1309484&Mask=2</span>
From the equation and with an enthalpy change of -231 kJ:
-231 kJ * 2 mol Mg * (1/-601.24 kJ/mol) = 0.76841 mol Mg
Then, with the molar mass of MgO = 40.3,
0.76841 mol Mg *(2 mol MgO/2 mol Mg)* 40.3 g/mol MgO = <span>30.967 g MgO</span>
Answer:
2C4H10 + 13O2 → 8CO2 + 10H2O
Hope this helps brainleist??
Explanation:
HClO₄ + KOH → KClO₄ + H₂O
HClO₄ - perchloric acid
KOH - potassium hydroxide
Answer:
0.5474
Explanation:
3.22 x 0.17
\/
322 x 17 = 5,474
[] There are four places "after" the decimal in 3.22 and 0.17 combined, meaning we move the decimal to the right four times in our current answer
-> 5,474 becomes 0.5474
Have a nice day!
I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly. (ノ^∇^)
- Heather
Answer:
kJ/mol
Explanation:
Given and known facts
Mass of Benzene 
grams
Mass of water 
grams
Standard heat capacity of water 
J/g∙°C
Change in temperature ΔT 
°C
Heat
Heat released by benzine is - 7.82 kJ
Now, we know that
grams of benzene release 
kJ heat
So, 
g benzine releases
kJ/g
mol C6H6
Heat released
kJ/mol
