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3 years ago

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Does bacteria need water to live

1 answer:

Aleks [24]3 years ago

6 0

No. bacteria only needs food to live along with other special needs depending on the type of bacteria

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Out of 13 students how many<br> saw themselves in the<br> horoscope?

Andru [333]

Answer: Astrology is not astronomy! ... Astronomers and other scientists know that stars many light years* away have no effect on the ... Imagine a straight line drawn from Earth through the Sun and out into space way ... The 13 constellations in the zodiac. ... on the phases of the Moon), each month got a slice of the zodiac all to itself.

Explanation: Hope this helps

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3 years ago

Which situation would lead to increased competition

I am Lyosha [343]

I would say B because c and d would decrease competition and a would do the same, or just kill the ecosystem.

Hope this helps and don't forget to hit that heart :)

8 0

2 years ago

Balance the equation <br> Ca(s) + H3PO4(aq) ---->Ca3(PO4)2(s) + H2(g)

vovikov84 [41]

Answer: CO2x+O4H I don’t know if this is the right answer

3 0

2 years ago

What is the limiting reactant for the following balanced equation when 9 moles of AlF3 are mixed with 12 miles of O2?

tamaranim1 [39]

<h2>Answer: $AlF_{3}$ </h2>

Explanation:

The chemical equation of the reaction that occurs when $AlF_{3}$ reacts with $O_{2}$ is

$4AlF_{3}+3O_{2}$ → $2Al_{2}O_{3}+6F_{2}$

$4$ moles of $AlF_{3}$ requires $3$ moles of $O_{2}$ .

$1$ mole of $AlF_{3}$ requires $\frac{3}{4}$ moles of $O_{2}$ .

Given that we have $9$ moles of $AlF_{3}$ .

$9$ moles of $AlF_{3}$ requires $\frac{3}{4}\times 9=6.75$ moles of $O_{2}$ .

But we have $12$ moles of $O_{2}$ .

So, $AlF_{3}$ will be consumed first.

So, $AlF_{3}$ is the limiting reagent.

3 0

3 years ago

What is the total pressure (in atm) inside of a vessel containing N2 exerting a partial pressure of 0.256 atm, He exerting a par

Bezzdna [24]

Answer: Total pressure inside of a vessel is 0.908 atm

Explanation:

According to Dalton's law, the total pressure is the sum of individual partial pressures. exerted by each gas alone.

$p_{total}=p_1+p_2+p_3$

$p_{N_2}$ = partial pressure of nitrogen = 0.256 atm

$p_{He}$ = partial pressure of helium = 203 mm Hg = 0.267 atm (760mmHg=1atm)

$p_{H_2}$ = partial pressure of hydrogen =39.0 kPa = 0.385 atm (1kPa=0.00987 atm)

Thus $p_{total}=p_{H_2}+p_{He}+p_{H_2}$

$p_{total}$ =0.256atm+0.267atm+0.385atm =0.908atm

Thus total pressure (in atm) inside of a vessel is 0.908

8 0

3 years ago

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