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Marina86 [1]
3 years ago
11

Does bacteria need water to live

Chemistry
1 answer:
Aleks [24]3 years ago
6 0
No. bacteria only needs food to live along with other special needs depending on the type of bacteria
You might be interested in
You need 270 ml of a 65% alcohol solution. on hand, you have a 90% alcohol mixture. how much of the 90% alcohol mixture and pure
olganol [36]

You must add 75 mL water to 195 mL 90 % alcohol to make 270 mL of 65 % alcohol.

<em>Step 1.</em> Calculate the volume of 90 % alcohol needed

You can use the dilution formula

<em>V</em>1×<em>C</em>1 = <em>V</em>2×<em>C</em>2

where

<em>V</em>1 and<em> V</em>2 are the volumes of the two solutions

<em>C</em>1 and <em>C</em>2 are the concentrations

You can solve the above formula to get

<em>V</em>2 = <em>V</em>1 × <em>C</em>1/<em>C</em>2

<em>V</em>1 = 270 mL; <em>C</em>1 = 65 %

V2 = ?; _____<em>C</em>2 = 90 %

∴<em>V</em>2 = 270 mL × (65 %/90 %) = 195 mL

You need 195 mL of 90 % alcohol to make 270 mL of 65 % RA

<em>Step 2</em>. Calculate the amount of water to add.

Volume of water = 270 mL – 195 mL = 75 mL

8 0
3 years ago
4. Finally, convert hemoglobin concentration from g/dL to millimoles per Liter (milliMolar or mM). Hemoglobin has a molecular we
prohojiy [21]

To make 1 Molar solution of hemoglobin ; 1600 grams of hemoglobin will be dissolved in 1 liter of water

The molecular weight of Hemoglobin is approximately  16,000 Daltons, when hemoglobin is converted to mM

16000 Dalton = 16000 ( g/mol )

given that 1 Dalton = 1 g/mol

To make 1 molar solution of hemoglobin using 1 liter of water

1 liter = 1000 grams

16000 Dalton = 16000 g/mol

Hence 16,000 grams of Hemoglobin is required to make 1 Molar solution of hemoglobin using 1 liter of water.

learn more : brainly.com/question/23517096

8 0
2 years ago
Which predator is typically found in Central Africa (but occasionally at geocode 34.043021, -118.2668356) and slays its opponent
noname [10]
I believe it is a black mamba.
6 0
3 years ago
What mass (in grams) of silver contains the same number of atoms as 5.59 grams of sulfur?
Amanda [17]

Answer:

18.84 g of silver.

Explanation:

We'll begin by calculating the number atoms present in 5.59 g of sulphur. This can be obtained as follow:

From Avogadro's hypothesis,

1 mole of sulphur contains 6.02×10²³ atoms.

1 mole of sulphur = 32 g

Thus,

32 g of sulphur contains 6.02×10²³ atoms.

Therefore, 5.59 g of sulphur will contain = (5.59 × 6.02×10²³) / 32 = 1.05×10²³ atoms.

From the calculations made above, 5.59 g of sulphur contains 1.05×10²³ atoms.

Finally, we shall determine the mass of silver that contains 1.05×10²³ atoms.

This is illustrated below:

1 mole of silver = 6.02×10²³ atoms.

1 mole of silver = 108 g

108 g of silver contains 6.02×10²³ atoms.

Therefore, Xg of silver will contain 1.05×10²³ atoms i.e

Xg of silver = (108 × 1.05×10²³)/6.02×10²³

Xg of silver = 18.84 g

Thus, 18.84 g of silver contains the same number of atoms (i.e 1.05×10²³ atoms) as 5.59 g of sulfur

7 0
2 years ago
Pls helps asap plssss !!!!
DerKrebs [107]

Answer:1 3 4 1 im pretty positive

5 0
2 years ago
Read 2 more answers
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