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3 years ago

What happens when chlorine from CFCs mixes with ozone?

Chemistry

1 answer:

Svetach [21]3 years ago

5 0

Answer:

Because they are extremely stable molecules, CFCs do not react easily with other chemicals in the lower atmosphere. ... Free chlorine atoms then react with ozone molecules, taking one oxygen atom to form chlorine monoxide and leaving an ordinary oxygen molecule.

Explanation:

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What type of reaction occurs between Mg and HCl and explain why?

lyudmila [28]

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3 years ago

Passing an electric current through a sample of water (H2O) can cause the water to decompose into hydrogen gas (H2) and oxygen g

Tema [17]

<u>Answer:</u> The mass of water that must be reacted is 56.28 grams.

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ ....(1)

Given mass of oxygen = 50 g

Molar mass of oxygen = 32.00 g/mol

Putting values in equation 1, we get:

$\text{Moles of oxygen}=\frac{50g}{32g/mol}=1.5625mol$

For the given chemical equation:

$2H_2O\rightarrow 2H_2+O_2$

By Stoichiometry of the reaction:

1 mole of oxygen is produced when 2 moles of water is reacted.

So, 1.5625 moles of oxygen is produced when = $\frac{2}{1}\times 1.5625=3.125mol$ of water is reacted.

To calculate the mass of water, we use equation 1:

Moles of water = 3.125 moles

Molar mass of water = 18.01 g/mol

Putting values in equation 1, we get:

$3.125mol=\frac{\text{Mass of water}}{18.01g/mol}\\\\\text{Mass of water}=56.28g$

Hence, the mass of water that must be reacted is 56.28 grams.

3 0

4 years ago

Find the final equilibrium temperature when 10.0 g of milk at 10. c is added to 1.60 x 10^2g of coffee with a temperature of 90.

IRINA_888 [86]

The concept that can be used in order to answer this item is that of the conservation of heat among the system. We let T be equal to the final temperature. The equation that would allow us to relate the initial and final conditions of both substances is as follows,

m₁cp₁(T - T₁) = m₂cp₂(T₂ - T)

The first entity, 1, is the milk and the second entity, 2, is the coffee. We are given that the specific heats of both substances are just equal so we can eliminate them from the equation. Substituting the known values,

(10 g)(T - 10°) = (1.60 x 10^2 g)(90° - T)

The value of T from the equation is 85.29°C.

Answer: 85.29°C

4 0

3 years ago