Y = -6.
-2(7)-2y=-2
-14-2y=-2
you need to move -14 to the other side by canceling out -14 with +14, and add +14 to -2, giving you -2y=12. -2/12=-6
The real solutions the equation as given in the task content; x² = 225 are; +25 and -25.
<h3>What are the real solutions of the equation as given in the task content?</h3>
It follows from the task content that the real solutions of the equation as given in the task content can be determined as follows;
x² = 225
x = ± 15
Therefore, the real solutions of the equation are; +25 and -25.
Read more on real solutions of equations;
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In distributive property, the answer would be 12(5 + 4j).
I’m not sure if this was a typo, but A and B are the same answer. A and B are correct, because when you solve this the answer has to be anything less than -0.6.
Answer:
The probabilty of having at least one pink bulb if 4 bulbs are purchased is 13%.
Step-by-step explanation:
The proportion of pink bulbs is p=0.4.
If X is the amount of pink bulbs in a group of 4 bulbs, we can model this as a binomial distribution problem.
The probability that at least one of the bulbs is pink is P(X≥1)
The probabilty of having at least one pink bulb if 4 bulbs are purchased is 13%.
