Answer:
the ion present in the original solution is Ca2+
Explanation:
Precipitation reactions occur when cations and anions in aqueous solution combine to form an insoluble ionic solid called a precipitate.
<u>Step1</u> : If we add Nacl to the solution, there is no precipitate formed
⇒The only possible ion that can form a precipate with Cl- is Ag+; since there is no precipitate formed, Ag+ is not present
<u>Step2</u> : If we add Na2SO4 to the solution, a white precipitate is formed
The possible ions to bind at SO42- are Ca2+ and Fe2+
But the white precipitate formed, points in the direction of Ca2+
⇒This means calcium is present
<u>Step3</u> : If we add Na2CO3 to the filtered solution, there is a precipate formed
Ca2+ will bind also with CO32- and form a precipitate
So the ion present in the original solution is Ca2+
A solid-state<span> phase </span>transformation<span> occurs when the interface between two grains that are chemically or structurally different moves.</span>
Permafrost soil (gelisol) is b) fragile.
Answer:
The answer to your question is E = 83.2 J
Explanation:
Data
Element: Gold
Initial temperature = T1 = 5°C
Final temperature = T2 = 37°C
mass = 20 g
Specific heat = 130 J/kg°K
Process
1.- Convert temperature to kelvin
T1 = 273 + 5 = 278°K
T2 = 273 + 37 = 310°K
2.- Convert mass to kg
1000 g --------------- 1 kg
20 g --------------- x
x = (20 x 1)/1000
x = 0.02 kg
3.- Formula
E = mC(T2 -T1)
4.- Substitution
E = (0.02)(130)(310 - 278)
E = (0.02)(130)(32)
E = 83.2 J
