All categories

3 years ago

What was important about the copernican revolution?

Chemistry

1 answer:

abruzzese [7]3 years ago

7 0

C i think because new info can be found to make a new idea

You might be interested in

What is CdF^4 compound name

topjm [15]

Answer:

well it might be 1.)Cadmium Fluoride CdF2 150.4078

2.)Cadmium(II) Perfluorate Cd(FO4) 2278.403

3.)Cadmium Ferrocyanide Cd2Fe(CN) 6436.7714

Explanation:

3 0

3 years ago

Suppose 2.4 g of Mg reacts with 10.0 g of O2, to create magnesium oxide. How much magnesium oxide is produced?

o-na [289]

Answer:

3.98 g

Explanation:

Step 1. Write the balanced chemical reaction. In this case, magnesium reacts with oxygen to produce magnesium oxide:

$2~Mg(s) + O_2 (g)\rightarrow 2~MgO (s)$

Step 2. Calculate the number of moles of magnesium:

$n_{Mg} = \frac{2.4~g}{24.305~g/mol} = 0.0987~mol$

Step 3. Calculate the number of moles of oxygen:

$n_{O_2} = \frac{10.0~g}{32.00~g/mol} = 0.3125~mol$

Step 4. Identify the limiting reactant comparing the equivalents. Equivalent of Mg:

$eq_{Mg} = \frac{0.0987~mol}{1} = 0.0987~mol$

Equivalent of oxygen:

$eq_{O_2} = \frac{0.3125~mol}{2} = 0.15625~mol$

Therefore, Mg is the limiting reactant.

Step 5. According to the stoichiometry of this reaction:

$n_{Mg} = n_{MgO} = 0.0987~mol$

Step 6. Convert the number of moles of MgO into mass:

$m_{MgO} = 0.0987~mol\cdot 40.304~g/mol = 3.98~g$

5 0

3 years ago

The pendulum has the greatest kinetic energy and no potential energy when it is _____.

Bad White [126]

Answer:

At the top of the swing

Explanation:

3 0

2 years ago

A 1.2 kg sample of Th-228 has a half-life of 1.9 years. How many grams of Th is left after 13.3 years?

Bumek [7]

.009375 kg or 9.375 grams will remain

7 0

3 years ago

vanillin is a flavoring agent in vanilla it has a mass percent composition of 61.15% c,5.3%H,31.55% o determine the empirical fo

Nutka1998 [239]

The empirical and molecular formulas will be $C_5H_5O_2$ and $C_1_0H_1_0O_4$ respectively.

<h3>Empirical and molecular formula</h3>

The compound contains C, H, and O.

C = 61.15/12 = 5.0958

H = 5.3/1 = 5.3

O = 31.55/16 = 1.9719

Divide by the smallest

C = 2.6

H = 2.7

O = 1

Thus, the empirical formula is $C_5H_5O_2$

Empirical formula mass = (12x5) + (1x5) + 16x2 = 97

n = 152.15/97 = 2

The molecular formula is $C_1_0H_1_0O_4$

More on molecular and empirical formulas can be found here: brainly.com/question/14425592

#SPJ1

6 0

2 years ago