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ratelena [41]
3 years ago
7

What is the reason for the low solubility of LiF (0.27 g

Chemistry
1 answer:
Brut [27]3 years ago
3 0

Answer:

The answer is C. The high solvation energy for LI+

Explanation:

LiF has lower solubility because of the high solvation energy of Li+ ion. This is due to the smaller  size and very big charge compared to Cs+ ion which has a bigger size and solvent molecules easily surround it.

Solvation energy is simply the amount energy that is required to make a solute dissolve in a solvent.

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natka813 [3]

4

I can confirm that's the correct answer

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2 years ago
Give an example of an oxidisation reaction!
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<span>When an atom or compound is oxidized, its properties change. For example, when an iron object undergoes oxidation, it is transformed because it has lost electrons. Unoxidized iron is a strong, structurally sound metal, while oxidized iron is a brittle, reddish powder. The diagram below illustrates what happens to an atom of iron as it is oxidized

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4 years ago
im found only in plant cells im as green as can be i make food for the plant using the suns energy what am i?
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im found only in plant cells im as green as can be i make food for the plant using the suns energy what am i?

ANS:-Chloroplast

7 0
3 years ago
Read 2 more answers
How do you create a neutrally buoyant object using 3 or more objects?
olga_2 [115]
It has to weigh the same weight as the amount of water it displaces. eg - if it weighs a kg, it would have to displaces exactly 1 litre of water
3 0
3 years ago
The substance fluorine has the following properties: normal melting point: 53.5 K normal boiling point: 85.0 K triple point: 1.6
mihalych1998 [28]

Answer:

The true statements include;

- The sample is initially a gas.

- The final state of the substance is a solid.

- One or more phase changes will occur.

The untrue/false statements include;

- The liquid initially present will vaporize.

- The final state of the substance is a liquid.

Explanation:

A couple pieces of informatton on Fluorine is imitially provided.

The substance fluorine has the following properties: normal melting point: 53.5 K normal boiling point: 85.0 K triple point: 1.6×10-4 atm, 53.4 K critical point: 55 atm, 144.1 K

So, a question is now attached about a sample of Fluorine. A sample of fluorine at a pressure of 1.00 atm and a temperature of 90.3 K is cooled at constant pressure to a temperature of 49.3 K.

We are then told to examine a group of options to find the ones that are correct/apply.

Taking the options one at a time

- The sample is initially a gas.

The initial state of the Fluorine sample has its temperature at 90.3 K, which is above the gas' boiling point. Hence, the sample can be concluded to initially be a gas.

- The liquid initially present will vaporize.

The sample doesn't initially contain liquid. And even of it did, the temperature is cooled, not heated , Hence, this statement is wrong.

- The final state of the substance is a solid.

The sample of Fluorine moves from a temperature higher than boiling point (85.0 K), with the sample in gaseous form, to one that is at a lower temperature (49.3 K) than the gas' normal melting point (53.5 K).

At temperatures lower than melting point, a substance exists in the solid form. Hence, this statement is true. The final state of the substance is solid.

- One or more phase changes will occur.

In moving from 90.3 K to 49.3 K for the sample and passing through the substance's boiling and melting points (85.0 K and 53.5 K respectively) along the way, it is logical to conclude that there would be one or more phase changes will occur. This statement is true.

- The final state of the substance is a liquid.

This is false as we already established that the final state of the substance is a solid. Hence, this statement is false.

Hope this Helps!!!

7 0
4 years ago
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