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ratelena [41]
3 years ago
7

What is the reason for the low solubility of LiF (0.27 g

Chemistry
1 answer:
Brut [27]3 years ago
3 0

Answer:

The answer is C. The high solvation energy for LI+

Explanation:

LiF has lower solubility because of the high solvation energy of Li+ ion. This is due to the smaller  size and very big charge compared to Cs+ ion which has a bigger size and solvent molecules easily surround it.

Solvation energy is simply the amount energy that is required to make a solute dissolve in a solvent.

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4 HF(g)+SiO2(s) → SiF4(9)+2 H2O(9) <br> Is the Si oxidized or reduced?
Airida [17]

Answer:

Si is reduced since it loses the oxygen atom

8 0
3 years ago
2CO(g)+O2 (g) =2CO2(g)
Ronch [10]

Answer:

6.76 moles.

Explanation:

2CO(g)+O2 (g) =2CO2(g)

When 2 CO mols were reacted with excess O2 then 2 mols of CO2 is created.

Therefore if 6.76 moles reacted, same number of CO2 will be created.

4 0
3 years ago
In which layer of the ocean do surface currents flow?
Marat540 [252]

Answer:

ooh sorry, but will this help you now:

Ocean dynamics define and describe the motion of water within the oceans. Ocean temperature and motion fields can be separated into three distinct layers: mixed (surface) layer, upper ocean (above the thermocline), and deep ocean. Ocean currents are measured in sverdrup (sv), where 1 sv is equivalent to a volume flow rate of 1,000,000 m (35,000,000 cu ft) per second.

Surface currents, which make up only 8% of all water in the ocean, are generally restricted to the upper 4…

Explanation:

Hope this helps :)

8 0
3 years ago
Based on the equation, how many grams of Br2 are required to react completely with 36.2 grams of AlCl3?
s2008m [1.1K]

Answer:

65.08 g.

Explanation:

  • For the reaction, the balanced equation is:

<em>2AlCl₃ + 3Br₂ → 2AlBr₃ + 3Cl₂,</em>

2.0 mole of AlCl₃ reacts with 3.0 mole of Br₂ to produce 2.0 mole of AlBr₃ and 3.0 mole of Cl₂.

  • Firstly, we need to calculate the no. of moles of 36.2 grams of AlCl₃:

<em>n = mass/molar mass</em> = (36.2 g)/(133.34 g/mol) = <em>0.2715 mol.</em>

<u><em>Using cross multiplication:</em></u>

2.0 mole of AlCl₃ reacts with → 3.0 mole of Br₂, from the stichiometry.

0.2715 mol of AlCl₃ reacts with → ??? mole of Br₂.

∴ The no. of moles of Br₂ reacts completely with 0.2715 mol (36.2 g) of AlCl₃  = (0.2715 mol)(3.0 mole)/(2.0 mole) = 0.4072 mol.

<em>∴ The mass of Br₂ reacts completely with 0.2715 mol (36.2 g) of AlCl₃ = no. of moles of Br₂ x molar mass</em> = (0.4072 mol)(159.808 g/mol ) = <em>65.08 g.</em>

4 0
3 years ago
The ion n3− has _____ protons and _____ electrons.enter your answers as integers separated by a comma.
bearhunter [10]
The ion N³⁻ is called the azide ion. In its neutral state, it occurs as the element Nitrogen. The atomic number of Nitrogen is 7. When it turns into an anion (negatively charged ion), it gains 3 more electrons. That's why its net charge becomes -3. It means that the protons is still 7, but the electrons are now 10. 

Overall charge = +7 + -10 = -3
5 0
3 years ago
Read 2 more answers
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