lasie4. A 4 kg object is displaced to the right by a distance of 12 m underthe influence of the following forces: a 17 Nforce pu
lling to the right, a 36 N force that makesan angle of 30 deg with the horizontal-right.Calculate the net work done on the object. (1 point)A. O 462.747 JB. O1096.557 JC. O151.221 JD. O 675.066 J
1 answer:
The work done by a constant force in a rectilinear motion is given by:
where F is the magnitude of the force, d is the distance and θ is the angle between the force and the displacement vector.
In this case we have two forces then we need to add the work done by each of them; for the first force we have a magnitude of 17 N, a displacement of 12 m and and angle of 0° (since both the displacement and the force point right); for the second force we have a magnitude of 36 N, a displacement of 12 m and an angle of 30°. Plugging these values we have that the total work is:
Therefore, the total work done is 578.123 J and the answer is option E
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Explanation:
Let's consider a radial field for simplicity. We have:
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where
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Answer:
Explanation:
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hope this helps!!