For the position of button we can use force balance as
Friction Force = Centripetal force
so here we will have
here we know that
R = radius of circle where button is placed
f = 35 rev/min
now from above equation
so friction coefficient will be 0.33
X =0.75,2 i hope this helps you
A. Medium 1 is air. The refractive index of air is 1.0003. Refractive index is a measure of the bending of a ray of light when passing from one medium to another. If i is the angle of incidence of a ray in vacuum and r is the angle of refraction, the refractive index n is defined as the ratio of the sine angle of incidence to the sine of the angle of refraction; that is, n= sin i/ sin r. Refractive index may also be given by the velocity of light in medium 1 divided by the velocity of light in medium 2.
b. In this case the refractive index = sin 72.5/sin 39.6
= 1.4962
but n = x/ 1.0003 = 1.4962
Therefore; x = 1.4967
Hence the refractive index of medium 2 is 1.4967.
I therefore think that medium 2 is toluene; since it has a similar refractive index.
Answer:
For an atom to have a balanced charged, the number of protons shall be equal to the number of electrons of an atom. proton is the positive part of an atom whereas electrons are the negative part of an atom. Only if the number of protons will be equal to the number of electron, the atom will be able to be neutral.
If the number of electron will be more, then the atom will be negative. If the number of electron will be less, then the atom will be positive.
From Newton's law v^2 = u^2 + 2as where a is the acceleration and s is the distance.
But to go any further, we need to know how fast the vehicle is accelerating
From v = u +at
We have a = u/t where the final velocity v = 0
So in one minute acceleration = (35 / 60) / 60 = 0.0097 ms/2. The first
experession in bracket is the initial velocity, u, in metres per seconds.
Hence v^2 = (0.583)^2 + 2 (0.0097)(30)
v^2 = 0.3398 + 0.5826 = 0.9224
v = âš 0.9224 = 0.960m
