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maria [59]
3 years ago
5

A 62.9 g sample of ground water is found to have a lead concentration of 13.97 ppm. Calculate the mass of lead in the sample in

milligrams.
Chemistry
1 answer:
netineya [11]3 years ago
3 0

Answer:

0.879 mg

Explanation:

To solve this problem we need to use the definition of ppm:

  • ppm = μg solute / g solution

With the above information in mind we can calculate the micrograms of lead using the concentration (13.97 ppm) and mass of solution (62.9 g):

  • μg lead = 13.97 ppm * 62.9 g
  • μg lead = 878.713 μg

Finally we convert μg to mg:

  • 878.713 μg *  \frac{1mg}{1000ug} = 0.879 mg of lead
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