For the quadratic y = x^2 -7x +12, when x = -3, what is the y-value?
2 answers:
Answer:
y = 0
Step-by-step explanation:
subsitute x = -3 into y = x^2 - 7x + 12
y = -3^2 - 7 x -3 + 12
= 9 - 21 + 12
= 0
Answer: 42
Step-by-step explanation:
y= (-3)^2 -7(-3) +12
= (9) -(-21) +12
= 9+21+12
= 42
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