The question is incomplete, here is the complete question:
The rate of certain reaction is given by the following rate law:
![rate=k[H_2]^2[I_2]^2](https://tex.z-dn.net/?f=rate%3Dk%5BH_2%5D%5E2%5BI_2%5D%5E2)
At a certain concentration of 
and 
, the initial rate of reaction is 4.0 × 10⁴ M/s. What would the initial rate of the reaction be if the concentration of
Answer : The initial rate of the reaction will be, 
Explanation :
Rate law expression for the reaction:
As we are given that:
Initial rate = 4.0 × 10⁴ M/s
Expression for rate law for first observation:
![4.0\times 10^4=k[H_2]^2[I_2]^2](https://tex.z-dn.net/?f=4.0%5Ctimes%2010%5E4%3Dk%5BH_2%5D%5E2%5BI_2%5D%5E2)
....(1)
Expression for rate law for second observation:
![R=k(\frac{[H_2]}{2})^2[I_2]^2](https://tex.z-dn.net/?f=R%3Dk%28%5Cfrac%7B%5BH_2%5D%7D%7B2%7D%29%5E2%5BI_2%5D%5E2)
....(2)
Dividing 2 by 1, we get:
![\frac{R}{4.0\times 10^4}=\frac{k(\frac{[H_2]}{2})^2[I_2]^2}{k[H_2]^2[I_2]^2}](https://tex.z-dn.net/?f=%5Cfrac%7BR%7D%7B4.0%5Ctimes%2010%5E4%7D%3D%5Cfrac%7Bk%28%5Cfrac%7B%5BH_2%5D%7D%7B2%7D%29%5E2%5BI_2%5D%5E2%7D%7Bk%5BH_2%5D%5E2%5BI_2%5D%5E2%7D)
Therefore, the initial rate of the reaction will be,
Answer:
A.
Explanation:
In the case of a seesaw, the object at the top is the effort and the object at the bottom is the load.
Answer:
1. 3.56 M.
2. 0.99 M.
Explanation:
¡Hola!
1. En este caso, dado que la molaridad de una solution es calculada por medio de la siguiente ecuación:
Es posible calcular la molaridad de 50 gramos de hidróxido de potasio primero calculando las moles en dicha masa por medio de la masa molar:
Luego, dado el volumen de la solución, podemos calcular la molaridad:
2. En este segundo ejercicio, procedemos de la misma manera, pues primero calculamos las moles de nitrato de potasio:
Luego, calculamos la molaridad justo como se hizo anteriormente:
Best regards!
The conversion factor between moles of calcium ion and moles of 
in would be 3 to 1.
<h3>Mole fraction</h3>
if formed from 3 carbon atoms and 3 phosphate atoms according to the equation:
Thus, there are 3 moles of calcium in every 1 mole of .
The conversion factor between moles of calcium and moles of will. therefore, be 3 to 1 or simply 3:1.
More on mole fractions can be found here: brainly.com/question/8076655
#SPJ1
They look like gases plasmas have no fixed shapes or volume and are less dense tan solids or liquids
