Hello!
If i have three moles of a gas at a pressure of 5.6 atm and a volume of 3 liters, what is the temperature ?
We have the following data:
n (number of moles) = 3 moles
P (pressure) = 5.6 atm
V (volume) = 12 L
T (temperature) = ? (in Kelvin)
R (gas constant) = 0.082 atm.L / mol.K
We apply the data above to the Clapeyron equation (gas equation), let's see:
Answer:
The temperature is approximately 205 Kelvin
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I Hope this helps, greetings ... Dexteright02! =)