Question

if i have 4 moles of a gas at a pressure of 5.6 atm and a volume of 12 liters, what is the temperature? (205 K)

Answer 1

Hello!

If i have three moles of a gas at a pressure of 5.6 atm and a volume of 3 liters, what is the temperature ?

We have the following data:

n (number of moles) = 3 moles

P (pressure) = 5.6 atm

V (volume) = 12 L

T (temperature) = ? (in Kelvin)

R (gas constant) = 0.082 atm.L / mol.K

We apply the data above to the Clapeyron equation (gas equation), let's see:

$P*V = n*R*T$

$5.6*12 = 4*0.082*T$

$67.2 = 0.328\:T$

$0.328\:T = 67.2$

$T = \dfrac{67.2}{0.328}$

$T = 204.8780488...$

$\boxed{\boxed{T \approx 205\:K}}\end{array}}\qquad\checkmark$

Answer:

The temperature is approximately 205 Kelvin

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I Hope this helps, greetings ... Dexteright02! =)