Answer:
Explanation:
speed is define as rate of change of distance or displacement
v=s/t
s=8 m
t=4s
v=8/4
v=2 m/s
Usually nice weather , i dont know the answer to the second part
Answer:
Energy will be
Explanation:
We have given that dielectric constant k = 5
Area of the plate ![A=0.027m^2](https://tex.z-dn.net/?f=A%3D0.027m%5E2)
Distance between the plates ![d=2mm=2\times 10^{-3}m](https://tex.z-dn.net/?f=d%3D2mm%3D2%5Ctimes%2010%5E%7B-3%7Dm)
Electric field E = 200 kN/C
We know that capacitance is given by ![C=\frac{K\epsilon _0A}{d}=\frac{5\times 8.85\times 10^{-12}\times 0.027}{2\times 10^{-3}}=0.597\times 10^{-9}F](https://tex.z-dn.net/?f=C%3D%5Cfrac%7BK%5Cepsilon%20_0A%7D%7Bd%7D%3D%5Cfrac%7B5%5Ctimes%208.85%5Ctimes%2010%5E%7B-12%7D%5Ctimes%200.027%7D%7B2%5Ctimes%2010%5E%7B-3%7D%7D%3D0.597%5Ctimes%2010%5E%7B-9%7DF)
We know that electric field is given by ![E=\frac{V}{d}](https://tex.z-dn.net/?f=E%3D%5Cfrac%7BV%7D%7Bd%7D)
So ![V=Ed=200\times 10^3\times 2\times 10^{-3}=400volt](https://tex.z-dn.net/?f=V%3DEd%3D200%5Ctimes%2010%5E3%5Ctimes%202%5Ctimes%2010%5E%7B-3%7D%3D400volt)
So energy will be ![E=\frac{1}{2}CV^2=\frac{1}{2}\times 0.597\times 10^{-9}\times 400^2=4.776\times 10^{-5}J](https://tex.z-dn.net/?f=E%3D%5Cfrac%7B1%7D%7B2%7DCV%5E2%3D%5Cfrac%7B1%7D%7B2%7D%5Ctimes%200.597%5Ctimes%2010%5E%7B-9%7D%5Ctimes%20400%5E2%3D4.776%5Ctimes%2010%5E%7B-5%7DJ)
Answer:
D. Because mass and energy are both conserved, the total amounts of mass and energy are the same before and after impact.
Explanation:
As we know that, the energy in motion is Kinetic Energy mathematically given as:
![KE=\frac{1}{2} m.v^2](https://tex.z-dn.net/?f=KE%3D%5Cfrac%7B1%7D%7B2%7D%20m.v%5E2)
<u>Now, according to the law of conservation of energy:</u>
![\frac{1}{2} m_1.u_1^2+\frac{1}{2} m_2.u_2^2=\frac{1}{2} m_1.v_1^2+\frac{1}{2} m_2.v_2^2](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%20m_1.u_1%5E2%2B%5Cfrac%7B1%7D%7B2%7D%20m_2.u_2%5E2%3D%5Cfrac%7B1%7D%7B2%7D%20m_1.v_1%5E2%2B%5Cfrac%7B1%7D%7B2%7D%20m_2.v_2%5E2)
where:
mass of racquet and ball respectively and
are their respective initial velocities.
are the respective final velocities.
<u>Also the law of conservation of momentum is applicable in this case:</u>
![m_1.u_1+ m_2.u_2= m_1.v_1+m_2.v_2](https://tex.z-dn.net/?f=m_1.u_1%2B%20m_2.u_2%3D%20m_1.v_1%2Bm_2.v_2)
In this case the velocity of the lighter mass will get increases in the final condition.