All categories

2 years ago

The force that keeps an object moving in a circle is called.

Physics

1 answer:

Sauron [17]2 years ago

7 0

If you mean rolling as in “moving in a circle”, that force would be the force of friction.

You might be interested in

A violin string has a standard length of 32.8 cm. It sounds the musical note A (440 Hz) when played without fingering. How far f

Rus_ich [418]

Answer:

The finger has to be placed at 5.25cm

Explanation:

The steps and appropriate formula in musical instrument is as shown in the attachment.

5 0

3 years ago

A 50 kg boy on ice skates throws a 5 kg ball to the left. If the ball ends up going 20 m/s. How fast is the boy going?

lukranit [14]

Answer:

He's going 4m/s per second

Explanation:

3tgk

6 0

3 years ago

Read 2 more answers

A woman is 1.6 m tall and has a mass of 50 kg. She moves past an observer with the direction of the motion parallel to her heigh

eduard

To solve this problem it is necessary to apply the concepts related to linear momentum, velocity and relative distance.

By definition we know that the relative velocity of an object with reference to the Light, is defined by

$V_0 = \frac{V}{\sqrt{1-\frac{V^2}{c^2}}}$

Where,

V = Speed from relative point

c = Speed of light

On the other hand we have that the linear momentum is defined as

P = mv

Replacing the relative velocity equation here we have to

$P = \frac{mV}{\sqrt{1-\frac{V^2}{c^2}}}$

$P^2 = \frac{m^2V^2}{1-\frac{V^2}{c^2}}$

$P^2 = \frac{P^2V^2}{c^2}+m^2V^2$

$P^2 = V^2 (\frac{P^2}{c^2}+m^2)$

$V^2 = \frac{P^2}{\frac{P^2}{c^2}+m^2}$

$V^2 = \frac{(2.1*10^10)^2}{\frac{(2.1*10^10)^2}{(3.8*10^8)^2}+50^2}$

$V = 2.81784*10^8m/s$

Therefore the height with respect the observer is

$l = l_0*\sqrt{1-\frac{V^2}{c^2}}$

$l = 1.6*\sqrt{1-\frac{(2.81*10^8)^2}{(3*10^8)^2}}$

$l = 0.56m$

Therefore the height which the observerd measure for her is 0.56m

8 0

3 years ago

A car takes 0.766 hours to drive 72.0 km to Georgia. How fast is the car going?<br> Please help

Karo-lina-s [1.5K]

Pretty fast. Everything looks fast when running past a light pole

8 0

3 years ago

Consider hitting a baseball with a bat. If we call the force on the bat against the ball the action force, identify the reaction

Nadya [2.5K]

Answer:

Explanation:

Action and reaction force are an integral part of third law of Newton . They are equal and opposite force - couple which act on two opposite objects. That is why they can not make a body in equilibrium.

In the given case, a bat is hit by a ball , at the point of contact , two equal and opposite forces emerge simultaneously , one acting on the ball and the other acting on the bat. As per the problem , force on the bat is called action . So the other force , that is force acting on the ball is called reaction force.

3 0

3 years ago