Test the value (x,y) of each point in the equation-y^2 + x <= -4 BY
1) because the equation has = so every point in the equation -y^2 + x = -4 is applied .... this case is B ... satisfy 2) A, E is in the same area choose one to test test A(-4,2) : -(2)^2 + (-4) <= -4 which is true the A and E is satisfy the inequality 3) no need to test fo C, D, F on the different area they are not satisfy. but you can guess it will satisfy -y^2 + x > -4
Answer:
Step-by-step explanation:
If MP bisects ∠BMS, then the line MP divides <BMS equally;
The adition postulate if therefore true;
<BMP +< PMS = <BMS and <BMP = < PMS
The equation becomes;
<BMP +< BMP= <BMS
2 <BMP = <BMS
2(2x+9) = 7x - 3
4x+18 = 7x-3
collect like terms
4x-7x = -3-18
-3x = -21
x = 21/3
x = 7
Since <BMP = < PMS 2x+9
< PMS = 2(7)+9
< PMS = 14+9
< PMS = 23
Hence the value of < PMS is 23
Answer:
1 is the value of x⁰ so this is the correct answer
Answer:
i am really not sure because i worked it out but i needed to see how they said it .
Step-by-step explanation:
