Lol
trouble varies directly as distance
lets say t=trouble and d=distance
t=kd
k is constant
given
when t=20, and d=400
find k
20=400k
divide by 400 both sides
1/20=k
t=(1/20)d
given, d=60
find t
t=(1/20)60
t=60/20
t=3
3 troubles
Answer:
15
proof on pic......................
Answer:
6/5
Step-by-step explanation:
hi! when dividing fractions, we use the KCF rule, which stands for keep,change,flip. we keep the first fraction the same, change the division symbol to multiplication, and flip the second fraction to its reciprocal. therefore, we now have:
9/10 * 4/3
now, we can multiply the numerators and denominators.
36/30
we can simplify this.
6/5
Answer:x-5
Step-by-step explanation:
