Answer:
the answer is b, there is more than one variable
Answer:
Number of peptide fragments resulting from cleaving with cyanogen bromide? A: Three peptide fragments
Number of peptide fragments resulting from cleaving with trypsin? A: Four peptide fragments
Which of these reagents gives the smallest single fragment (in number of amino acid residues)? A: CnBr, a dipeptide fragment consisting of AL (Alanine-Leucine)
Explanation:
Cyanogen bromide cleaves the methionine C-terminus, then we have a first fragment of 8 amino acids: DSRLSKTM, a second fragment of 15 aas YSIEAPAKLDWEQNM, and a last fragment of only 2 aas is produced, AL
Trypsin cuts the C-terminus of Arginine and Lysine, then we'll have a first fragment of 3 aas DSR, a second fragment consisting of also 3 aas LSK, a third fragment of 10 aas TMYSIEAPAK, and a last fragment of 9 aas LDWEQNMAL. All produced in three cut sites.
There are 32 atoms
12 in hydrogen
4 in phosphorus
16 in oxygen
Answer:
The answer to your question is: letter B
Explanation:
The information given is showing us three kinds of carbons and their respective number of protons and neutrons. Now, let's analize the options given:
A.)Carbon Bond Types This option is about trhe kind of bonds carbon is able to form like single, double or triple and is different from the information descrive above. So ,this option is incorrect.
B.)Carbon Isotopes is option is about the carbon atoms that have the same number of protons and different amount of neutrons exactly as it is describe above, to this option is correct.
C.)The Carbon Cycle
this option is about how carbon goes from one kind of matter to another and is completely different to the description given above, so this option is incorrect.
D.)Chemical Reactions this option is about reactants that after a process give products they could be from carbon -12, carbon-13 or carbon-14 and other elements, so this option is different from the description given above.