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PIT_PIT [208]
4 years ago
12

An overhead electric power line carries a maximum current of 125 A. What is the magnitude of the maximum magnetic field at a poi

nt 4.50 m directly below the power line
Physics
1 answer:
BARSIC [14]4 years ago
3 0

Answer:

B= 55.6×10^(-7) Tesla

Explanation:

B= μoI/(2πr)

B:  magnetic field strength

μo: permeability of free space and is equal to  4π×10^(-7) T.m/A

r: distance from the wire

I : current in the wire

B= (4π×10^(-7)×125)/(2π×4.5)

B= 55.6×10^(-7) Tesla

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agasfer [191]

Total work done is 0.13 Joules

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3 years ago
A boy is whirling a stone around his head by means of a string. The string makes one complete revolution every second, and the t
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The tension increases to four times its original value.

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v = Velocity

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T=m\dfrac{v^2}{r}

\\\Rightarrow T\propto v^2

\dfrac{T_1}{T_2}=\dfrac{v_1^2}{v_2^2}\\\Rightarrow \dfrac{T_1}{T_2}=\dfrac{v_1}{2^2v_1^2}\\\Rightarrow \dfrac{T_1}{T_2}=\dfrac{1}{4}\\\Rightarrow T_2=4T_1

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Which orbit has the highest energy?<br> n = 1<br> n = 2<br> n = 3
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