Answer:
Explanation:
The experimenter is rotating on his stool with angular velocity ω ( suppose )
His moment of inertia is I say
We are applying no torque from outside . therefore , the angular momentum will remain the same
Thus angular momentum L = I ω = constant
Thus we can say I₁ ω₁ = I₂ω₂ = constant
here I₁ is the initial moment of inertia and ω₁ is the initial angular velocity
Similarly I₂ is the final moment of inertia and ω₂ is the final angular velocity
When a been bag is dropped on his lap , his moment of inertia increases due to increase in mass
In the above equation, when moment of inertia increases , the angular velocity decreases . So its motion of rotation will decrease .
Changes in state of matter would be a physical change to whatever it is that you are changing so I think it would be B.Molecules because in order for something to change the molecules have to be moving apart from one another but I maybe wrong depending on what it is your looking at
With 30degree because incident angle = reflected angle
Answer:
A) F = 1.8375 N, B) V = 1.25 10⁻⁴ m³, C) V= 1.25 10⁻⁴ m³
Explanation:
This exercise should select some values such as the weight of the block m=0.250 kg and the density of the liquid ρ = 500 kg / m³ (water); with these values answer the question, for this we use the static equilibrium relations.
Σ F = 0
F + B - W = 0
the expression for thrust is
B = ρ g V_liquid
A) the weight of the block is
W = m g
W = 0.250 9.8
W = 2.45 N
Let's look for the maximum push
V_body = V_liquid
B = 500 9.8 0.05³
B = 0.6125 N
we substitute
F = W - B
F = 2.45 - 0.6125
F = 1.8375 N
B) As the body is totally submerged, the volume of the liquid and the body are equal
V = l³
V = 0.05³
V = 1.25 10⁻⁴ m³
C) the volume of water displaced is equal to the volume of the body
V_liquid = 1.25 10⁻⁴ m³
A storm because nobody can control it.
