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lukranit [14]
3 years ago
11

Los neutrones tienen carga eléctrica———-y masa de ——una

Chemistry
1 answer:
3241004551 [841]3 years ago
6 0

Answer:

thanks for your points

God bless you ALWAYS

and pa follow

at pa brainlest answer please

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The vapor pressure of a liquid __________.
mash [69]

Answer:

B

Explanation:

The tendency of a liquid to convert to vapour increases smoothly with increasing temperature. Vapour pressure shows the tendency of a liquid to convert to vapour. Increase In vapour pressure shows an increased tendency to convert to vapour. The higher the temperature, the higher the vapour pressure.

6 0
3 years ago
Which of the following does each different kind of atom represent?
3241004551 [841]

Answer:

Element

Explanation:

Each different kind of atom represents an atom. Elements like atoms are considered to be distinct substances that cannot be split into simpler substances. Such substances are known to be made up of just one kind of atom.

Like an atom, elements are made up of protons, neutrons and electrons. Both the protons and neutrons are found in the nucleus of the atom.

3 0
3 years ago
Make the selection that best completes the sentence.
mylen [45]
The answer would be C. in an ellipse

Hope this answer helps!
5 0
3 years ago
Read 2 more answers
If 12.8 g lead(II) sulfate (303.3 g/mol) precipitates when excess potassium chloride is added to 1.65 L of a water sample, what
quester [9]

Answer:

M=0.0256M

Explanation:

Hello,

In this case, the undergoing chemical reaction is:

PbSO_4(aq)+2KCl(aq)\rightarrow PbCl_2(s)+K_2SO_4(aq)

In such a way, since all the lead (II) is converted due to the excess of potassium chloride, the moles of lead (II) in the sample are computed from the mass of lead (II) sulfate:

n_{Pb^{2+}}=12.8gPbSO_4*\frac{1molPbSO_4}{303.3gPbSO_4} *\frac{1molPb^{2+}}{1molPbSO_4} \\\\n_{Pb^{2+}}=0.0422molPb^{2+}

Thus, since volume of the solution is 1.65 due to the fact that the addition of the reactants is not enough to significantly modify the reaction's volume, the resulting molar concentration of the lead (II) ions is:

M=\frac{n_{Pb^{2+}}}{V}=\frac{0.0422molPb^{2+}}{1.65L}\\  \\M=0.0256M

Regards.

5 0
3 years ago
I need help with this, Please help.
LUCKY_DIMON [66]

Answer:

b

Explanation:

5 0
3 years ago
Read 2 more answers
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