How do metals become stable?

Chemistry

1 answer:

natali 33 [55]3 years ago

8 0

Answer:

Atoms of metal elements give away electrons in their reactions to form positive ions. The ions formed have a full outer electron shell, so are very stable.

Explanation:

To become stable, the metal atom wants to get rid of one or more electrons in its outer shell. ... Alternately, an atom that loses electrons becomes a positively charged ion (aka cations). The particles in an ionic compound are held together because there are oppositely charged particles that are attracted to one another.

You might be interested in

CAN SOMEONE HELP ME PLEASE ?

kkurt [141]

The correct is answer is A, because fertilizer provides nitrogen to plants

5 0

3 years ago

Select the best definition of salt water:

hoa [83]

Water that contains large amounts of disolved salts

4 0

2 years ago

Read 2 more answers

Use the Rydberg equation to calculate the wavelength (in Å) of the photon absorbed when a hydrogen atom undergoes a transition f

ivolga24 [154]

Answer:

1024Å

Explanation:

The Rydberg equation is an empirical relationship equation expressed by Balmer and Rydberg which is given as:

1/λ = $R_{H} (\frac{1}{n_{f} ^{2} }-\frac{1}{n_{i} ^{2} } )$ .............................(1)

where $R_{H}$ is the Rydberg constant given as $1.09 x 10^{7}m^{-1}$ , n is the transition level and the subscript f and i show the final and initial level numbers respectively. λ is the wavelength.

$n_{f}$ = 1

$n_{i} = 3$

Using equation (1), we have

1/λ $= 1.097 x 10^{7}(\frac{1}{3^{2} }- \frac{1}{1^{2} })$

= $1.097 x 10^{7} (\frac{1}{9} -\frac{1}{1} )$

= $1.097 x 10^{7}(0.11-1)$

= $1.097 x 10^{7} (-0.89)$

= - 9763300

λ = $-\frac{1}{9763300}$

= $-1.024x 10^{-7}m$

We should note that the negative sign we have is as a result of photon absorption whereby the hydrogen atom gains energy to undergo a transition from the lower energy level to a higher one. Wavelength does not have a negative value.

To convert to Å, we have

λ = $\frac{1.024 x 10^{-7} }{10^{-10} }$ = 1024Å