Answer:
Where Blocal = local magnetic field between the two regions of the molecule
Blocal = (1-σ)B0
ΔBlocal = (1-σ1)B0 - (1-σ2)B0 = (σ2 - σ1)B0 = ΔσB0 ≈ ΔδB0 x 10∧-6
= (3.36-1.16) x 10∧-6 x B0 = 2.20 x 10∧-6B0
(a) ΔBlocal = 2.20 x 10∧-6 x 1.9T = 4.2 μT
(b) ΔBlocal = 2.20 x 10∧-6 x 16.5T = 36.3 μT
Explanation:
Can't understand this. English Please! :) :)
Answer:
<u>ATGGCCTA</u>
Explanation:
For this we have to keep in mind that we have a <u>specific relationship between the nitrogen bases</u>:
-) <u>When we have a T (thymine) we will have a bond with A (adenine) and viceversa</u>.
-) <u>When we have C (Cytosine) we will have a bond with G (Guanine) and viceversa</u>.
Therefore if we have: TACCGGAT. We have to put the corresponding nitrogen base, so:
TACCGGAT
<u>ATGGCCTA</u>
<u></u>
I hope it helps!
Remember that
- For being a bond covalent ∆E<1.8
- For being a bond ionic ∆E>1.8
#1
Carbon is present so it's covalent
#2
#3
- P-H will hardly form a bond
#4
#5
Answer:
0.00013
Explanation:
I'm pretty sure. I first subtracted 1.87 from 2. I got 0.13. The conversion from mL to L is 0.001. I multiplied 0.13 and 0.001 and got <u>0.00013 mL.</u>
