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ivolga24 [154]
2 years ago
14

Explain preparation of alkanes C--C from industrial source for industrial preparation of alkane​

Chemistry
1 answer:
Dmitrij [34]2 years ago
4 0
Alkanes can be prepared from carboxylic acid via the removal of carbon dioxide. This process is known as decarboxylation. It produces alkane with a carbon atom lesser than that present in the carboxylic acid.
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11. A new compound has just been developed. Its formula is:
jarptica [38.1K]

Answer:

6.

Explanation:

G, H, O, N, Na, P

There are 6 different elements listed, with O (oxygen) showing up twice.

7 0
3 years ago
What is the maximum mass of b4c that can be formed from 2.00 moles of boron(iii) oxide?
anzhelika [568]

The maximum mass of B₄C that can be formed from 2.00 moles of boron (III) oxide is 55.25 grams.

<h3>What is the stoichiometry?</h3>

Stoichiometry of the reaction gives idea about the relative amount of moles of reactants and products present in the given chemical reaction.

Given chemical reaction is:

2B₂O₃ + 7C → B₄C + 6CO

From the stoichiometry of the reaction, it is clear that:

2 moles of B₂O₃ = produces 1 mole of B₄C

Now mass of B₄C will be calculated by using the below equation:

W = (n)(M), where

  • n = moles = 1 mole
  • M = molar mass = 55.25 g/mole

W = (1)(55.25) = 55.25 g

Hence required mass of B₄C is 55.25 grams.

To know more about stoichiometry, visit the below link:

brainly.com/question/25829169

#SPJ1

3 0
2 years ago
Consider the reaction: CaCO3(s) à CaO(s) + CO2(g)
Vsevolod [243]

Answer:

131.5 kJ

Explanation:

Let's consider the following reaction.

CaCO₃(s) → CaO(s) + CO₂(g)

First, we will calculate the standard enthalpy of the reaction (ΔH°).

ΔH° = 1 mol × ΔH°f(CaO(s)) + 1 mol × ΔH°f(CO₂(g) ) - 1 mol × ΔH°f(CaCO₃(s) )

ΔH° = 1 mol × (-634.9 kJ/mol) + 1 mol × (-393.5 kJ/mol) - 1 mol × (-1207.6 kJ/mol)

ΔH° = 179.2 kJ

Then, we calculate the standard entropy of the reaction (ΔS°).

ΔS° = 1 mol × S°(CaO(s)) + 1 mol × S°(CO₂(g) ) - 1 mol × S°(CaCO₃(s) )

ΔS° = 1 mol × (38.1 J/mol.K) + 1 mol × (213.8 J/mol.K) - 1 mol × (91.7 J/mol.K)

ΔS° = 160.2 J/K = 0.1602 kJ/K

Finally, we calculate the standard Gibbs free energy of the reaction at T = 25°C = 298 K.

ΔG° = ΔH° - T × ΔS°

ΔG° = 179.2 kJ - 298 K × 0.1602 kJ/K

ΔG° = 131.5 kJ

6 0
3 years ago
Define the term Symmetry? and explain its types
nika2105 [10]

Answer:

Mathematically, symmetry means that one shape becomes exactly like another when you move it in some way: turn, flip or slide. ... There are three basic types of symmetry: rotational symmetry, reflection symmetry, and point symmetry.

5 0
3 years ago
An atom of sodium-23 (Na-23) has a net charge of
maksim [4K]

Answer:

Protons= 11

neutrons= 12

electrons = 10

Explanantion:

Look for Na on periodic table

Atomic Number = 11

Atomic Mass = 23 (round it to be an integer)

Number of protons = Atomic number = 11

Number of neutrons = Atomic mass - atomic number = 23-11 =12

Number of electrons = 11 - e = ´+1 , electrons = 10

6 0
3 years ago
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