Answer:
1.) 13 g C₄H₁₀
2.) 41 g CO₂
Explanation:
To find the mass of propane (C₄H₁₀) and carbon dioxide (CO₂), you need to (1) convert mass O₂ to moles O₂ (via molar mass), then (2) convert moles O₂ to moles C₄H₁₀/CO₂ (via mole-to-mole ratio from equation coefficients), and then (3) convert moles C₄H₁₀/CO₂ to mass C₄H₁₀/CO₂ (via molar mass). It is important to arrange the ratios in a way that allows for the cancellation of units. The final answers should have 2 sig figs to match the sig figs of the given value.
Molar Mass (C₄H₁₀): 4(12.011 g/mol) + 10(1.008 g/mol)
Molar Mass (C₄H₁₀): 58.124 g/mol
Molar Mass (CO₂): 12.011 g/mol + 2(15.998 g/mol)
Molar Mass (CO₂): 44.007 g/mol
Molar Mass (O₂): 2(15.998 g/mol)
Molar Mass (O₂): 31.996 g/mol
2 C₄H₁₀ + 13 O₂ ----> 8 CO₂ + 10 H₂O
48 g O₂ 1 mole 2 moles C₄H₁₀ 58.124 g
--------------- x ----------------- x -------------------------- x ------------------ =
31.996 g 13 moles O₂ 1 mole
= 13 g C₄H₁₀
48 g O₂ 1 mole 8 moles CO₂ 44.007 g
--------------- x ----------------- x -------------------------- x ------------------ =
31.996 g 13 moles O₂ 1 mole
= 41 g CO₂
The correct answer is: [C]: "polar" .
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" Water " ; which is: " H₂O " ;
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is a:
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— polar; → {eliminate: "Choice [A]: "non-polar"} ;
→ {and consider: "Choice: [C]: "polar" } ;
— covalent; → {not "ionic"; eliminate: "Choice: [B]: "ionic"} ;
— uncharged; → {neutral compound; not "charged" —but "balanced"} ;
→ {Note: " H ⁺ , O ²⁻ ; → " H₂O " } ;
→ The "charges" balance/ cancel out.
→ {eliminate: "Choice: [D]: "charged" .}.
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— compound.
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The correct answer is: [C]: "polar" .
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Answer:
Whether you get the metal or hydrogen during electrolysis depends on the position of the metal in the reactivity series: the metal will be produced if it is less reactive than hydrogen. hydrogen will be produced if the metal is more reactive than hydrogen.
Answer:
What is the specific heat for the aluminum wire?
0.82
What is the specific heat for the steel wire?
0.47
What is the specific heat for the lead pellets?
0.25
Explanation:
Answer:
c is speed of light (in terms of velocity)
v is velocity
lambda is wavelength
Explanation:
speed of light is constant at 3 x 10^8 m/s which is a velocity value. Lambda is usually in the units of nanometers which represents wavelength.
