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3 years ago

Which best explains why collective bargaining increases the bargaining power of workers?

2 answers:

8 0

In the above question, options are not given so the answer has been generalized.

Collective bargaining power gives rights to the workers to put their demands in front of employer in a better way. It puts the workers and employers on the same level.
Collective bargaining increases the power of bargaining of workers. If the workers and employers have agreed on a collective bargaining on mandatory subjects then it is unfair for the employer to refuse.

Goshia [24]3 years ago

8 0

The answer to this question is It's difficult for employers to replace their entire work force.

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In prolonged fasting conditions acetyl-coa generated from the breakdown of amino acids and fatty acids does not enter the citric

Brums [2.3K]

In prolonged fasting conditions acetyl-coa generated from the breakdown of amino acids and fatty acids does not enter the citric acid cycle in the liver, but acetyl-coa derived from ketone bodies can enter the citric acid cycle in the brain. <u>Cholesterol is required in the diet.</u>

<h3>What is amino acids?</h3>

Amino acids are chemical molecules having side chains (R groups) unique to each amino acid as well as amino and carboxylic acid (CO2H) functional groups.

Every amino acid contains the elements carbon (C), hydrogen (H), oxygen (O), and nitrogen (N) (CHON); in addition, the side chains of cysteine and methionine contain sulfur (S), while the less frequent amino acid selenocysteine has selenium (Se). As of 2020, it is known that more than 500 naturally occurring amino acids make up the monomer units of peptides, including proteins.

Despite the fact that there are only 22 proteins, 20 of them have unique specified codons, and another two have unique coding mechanisms: All eukaryotes contain selenocysteine, and pyrrolysine is also present.

To learn more about amino acids from the given link:

brainly.com/question/21327676

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7 0

2 years ago

5.0 g of copper was heated from 20°C to 80°C. How much energy was used to heat Cu?

ale4655 [162]

Answer:

100 J of energy are needed to heat the copper from 20∘C to 80∘C .

5 0

3 years ago

A chemist fills a reaction vessel with 9.20 atm nitrogen monoxide (NO) gas, 9.15 atm chlorine (CI) gas, and 7.70 atm nitrosyl ch

ivanzaharov [21]

Answer:

The reactions free energy $\Delta G = -49.36 kJ$

Explanation:

From the question we are told that

The pressure of (NO) is $P_{NO} = 9.20 \ atm$

The pressure of (Cl) gas is $P_{Cl} = 9.15 \ atm$

The pressure of nitrosly chloride (NOCl) is $P_{(NOCl)} = 7.70 \ atm$

The reaction is

$2NO_{(g)} + Cl_2 (g)$ ⇆ $2 NOCl_{(g)}$

From the reaction we can mathematically evaluate the $\Delta G^o$ (Standard state free energy ) as

$\Delta G^o = 2 \Delta G^o _{NOCl} - \Delta G^o _{Cl_2} - 2 \Delta G^o _{NO}$

The Standard state free energy for NO is constant with a value

$\Delta G^o _{NO} = 86.55 kJ/mol$

The Standard state free energy for $Cl_2$ is constant with a value

$\Delta G^o _{Cl_2} = 0kJ/mol$

The Standard state free energy for $NOCl$ is constant with a value

$\Delta G^o _{NOCl} =66.1kJ/mol$

Now substituting this into the equation

$\Delta G^o = 2 * 66.1 - 0 - 2 * 87.6$

$= -43 kJ/mol$

The pressure constant is evaluated as

$Q = \frac{Pressure \ of \ product }{ Pressure \ of \ reactant }$

Substituting values

$Q = \frac{(7.7)^2 }{(9.2)^2 (9.15) } = \frac{59.29}{774.456}$

$= 0.0765$

The free energy for this reaction is evaluated as

$\Delta G = \Delta G^o + RT ln Q$

Where R is gas constant with a value of $R = 8.314 J / K \cdot mol$

T is temperature in K with a given value of $T = 25+273 = 298 K$

Substituting value

$\Delta G = -43 *10^{3} + 8.314 *298 * ln [0.0765]$

$= -43-6.36$

$\Delta G = -49.36 kJ$

4 0

3 years ago

In the laboratory you are asked to make a 0.175 m barium iodide solution using 13.9 grams of barium iodide. How much water shoul

BARSIC [14]

<u>Answer:</u> The mass of water that should be added in 203.07 grams

<u>Explanation:</u>

To calculate the molality of solution, we use the equation:

$\text{Molality}=\frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ (in grams)}}$

Where,

m = molality of barium iodide solution = 0.175 m

$m_{solute}$ = Given mass of solute (barium iodide) = 13.9 g

$M_{solute}$ = Molar mass of solute (barium iodide) = 391.14 g/mol

$W_{solvent}$ = Mass of solvent (water) = ? g

Putting values in above equation, we get:

$0.175=\frac{13.9\times 1000}{391.14\times W_{solvent}}\\\\W_{solvent}=\frac{13.9\times 1000}{391.14\times 0.175}=203.07g$

Hence, the mass of water that should be added in 203.07 grams

4 0

3 years ago

I need the answer today!

olchik [2.2K]

_____________________________________________

<h2 /><h2 /><h2><u>Solution </u><u>3</u><u> Is The Most Concentrated</u></h2>

M = m/v

= 100ml ÷ 2 spoons × 100%

= - 5,000 μg/ppb³

= <u>50% Diluted</u>

M = m/v

= 200ml ÷ 5 spoons × 100%

= - 4,000 μg/ppb³

= <u>40% Diluted</u>

M = m/v

= 300ml ÷ 6 spoons × 100%

= - 5,000 μg/ppb³

= <u>50% Diluted</u>

M = m/v

= 600ml ÷ 8 spoons × 100%

= - 75,000 μg/ppb³

= <u>75% Diluted</u>

_____________________________________________

8 0

3 years ago