Answer:
8.59 g
2.25 g
Explanation:
According to the given situation the calculation of grams of PbO and grams of NaCL is shown below:-
Moles of Pb(OH)CL is
= 0.0385 mol
Mass of PbO needed is
After solving the above equation we will get
= 8.59 g
Mass of NaCL needed is
After solving the above equation we will get
= 2.25 g
Therefore we have applied the above formula.
Answer:
Explanation:
So, the formula for the compound should be:
Now we assume that we have 1 mol of substance, so we can make calculations to know the molar mass of element X, as follows:
So we have that 6 moles weight 212.7g, and we can make a rule of three to know the weight of compound X:
As we used 1 mol, we know that the molar mass is 32.06g/mol
So the element has a molar mass of 32.06 g/mol and an oxidation state of +6, with this information, we can assure that the element X is sulfur, so the compound is
Answer: There is one way to write it but i’ll also provide an unbalanced equation and a balanced one.
Explanation:
Unbalanced : Ba (aq) + Cl2 (aq)—-> BaCl (aq)
Balanced : 2Ba (aq) + Cl2 (aq)—> 2BaCl(aq)
