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Studentka2010 [4]
3 years ago
12

Which of the following is a definition of a base? O a. behaves as a catalyst. O b. accepts H ions from acids. Oc. turns cloudy w

hen dissolved in water O d. donates H ions when dissolved in water O e. releases heat when dissolved in water
Chemistry
1 answer:
yan [13]3 years ago
5 0

Answer: b. accepts H^+ ions from acids

Explanation:

According to Arrhenius concept, a base is defined as a substance which donates hydroxide ions (OH^-) when dissolved in water and an acid is defined as a substance which donates hydronium ions (H_3O^+) in water.

According to the Bronsted Lowry conjugate acid-base theory, an acid is defined as a substance which donates H^+ ions and a base is defined as a substance which accepts H^+ ions.

NH_3+H_2O\rightarrow NH_4^++OH^-

Here water is donating H^+ ions, and thus act as acid and ammoia NH_3 is accepting H^+ ions from water and thus is a base.

According to the Lewis concept, an acid is defined as a substance that accepts electron pairs and base is defined as a substance which donates electron pairs.

Thus base is a substance which accepts  H^+ ions from acids.

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Hydrogen bonds form between neighboring water molecules because of:
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Read 2 more answers
Consider the reaction below. Initially the concentration of SO2Cl2 is 0.1000 M. Solve for the equilibrium concentration of SO2Cl
tensa zangetsu [6.8K]

Answer:

[SO_2Cl_2] = 0.09983 M

Explanation:

Write the balance chemical equation ,

SO_2Cl_2((g) = SO_2(g) + Cl_2(g)

initial concenration of SO_2Cl_2((g)  =0.1M

lets assume that degree of dissociation=\alpha

concenration of each component at equilibrium:

[SO_2Cl_2] = 0.1-0.1\alpha

[SO_2] = 0.1\alpha

[Cl_2] = 0.1\alpha

Kc =\frac{0.1\alpha \times 0.1\alpha}{0.1-0.1\alpha}

Kc =\frac{0.1\alpha \times \alpha}{1-\alpha}

as \alpha is very small then we can neglect  1-\alpha

therefore ,

Kc ={0.1\alpha \times \alpha}

\alpha =\sqrt{\frac{Kc}{0.1}}

\alpha = 1.73 \times 10^{-3}

Eqilibrium concenration of [SO_2Cl_2] = 0.1-0.1\alpha = 0.1-0.1\times 0.00173

[SO_2Cl_2] = 0.09983 M

4 0
3 years ago
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