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3 years ago

Which subatomic particles takes up most of the space of an atom

Chemistry

2 answers:

Vadim26 [7]3 years ago

7 0

The neutrons take up most of the space of an atom

Pavlova-9 [17]3 years ago

5 0

I believe electrons take up most of the space of an atom.

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5. What is the volume of 10 moles of a gas at 300 K held at a pressure of 3.5 atm?

Helga [31]

70.33 L is the volume of 10 moles of a gas at 300 K held at a pressure of 3.5 atm.

<h3>What is volume?</h3>

Volume is the percentage of a liquid, solid, or gas's three-dimensional space that it occupies.

Liters, cubic metres, gallons, millilitres, teaspoons, and ounces are some of the more popular units used to express volume, though there are many others.

We will use ideal gas law to find the volume

PV = nRT

Can also be written as

V = (nRT)/P

Where,

P = pressure

V = volume

n = amount of substance

R = ideal gas constant

T = temperature

Here, we have given

P = 3.5 atm

V = to find

n = 10 moles

R = 0.08206 L⋅atm/K⋅mol

T = 300k

Lets substitute the values

V = (10 × 0.08206 × 300)/3.5

V = 70.33 L

Learn more about volume

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3 0

1 year ago

Consider the reaction

SOVA2 [1]

Answer :

(a) The average rate will be:

$\frac{d[Br_2]}{dt}=9.36\times 10^{-5}M/s$

(b) The average rate will be:

$\frac{d[H^+]}{dt}=1.87\times 10^{-4}M/s$

Explanation :

The general rate of reaction is,

$aA+bB\rightarrow cC+dD$

Rate of reaction : It is defined as the change in the concentration of any one of the reactants or products per unit time.

The expression for rate of reaction will be :

$\text{Rate of disappearance of A}=-\frac{1}{a}\frac{d[A]}{dt}$

$\text{Rate of disappearance of B}=-\frac{1}{b}\frac{d[B]}{dt}$

$\text{Rate of formation of C}=+\frac{1}{c}\frac{d[C]}{dt}$

$\text{Rate of formation of D}=+\frac{1}{d}\frac{d[D]}{dt}$

$Rate=-\frac{1}{a}\frac{d[A]}{dt}=-\frac{1}{b}\frac{d[B]}{dt}=+\frac{1}{c}\frac{d[C]}{dt}=+\frac{1}{d}\frac{d[D]}{dt}$

From this we conclude that,

In the rate of reaction, A and B are the reactants and C and D are the products.

a, b, c and d are the stoichiometric coefficient of A, B, C and D respectively.

The negative sign along with the reactant terms is used simply to show that the concentration of the reactant is decreasing and positive sign along with the product terms is used simply to show that the concentration of the product is increasing.

The given rate of reaction is,

$5Br^-(aq)+BrO_3^-(aq)+6H^+(aq)\rightarrow 3Br_2(aq)+3H_2O(l)$

The expression for rate of reaction :

$\text{Rate of disappearance of }Br^-=-\frac{1}{5}\frac{d[Br^-]}{dt}$

$\text{Rate of disappearance of }BrO_3^-=-\frac{d[BrO_3^-]}{dt}$

$\text{Rate of disappearance of }H^+=-\frac{1}{6}\frac{d[H^+]}{dt}$

$\text{Rate of formation of }Br_2=+\frac{1}{3}\frac{d[Br_2]}{dt}$

$\text{Rate of formation of }H_2O=+\frac{1}{3}\frac{d[H_2O]}{dt}$

Thus, the rate of reaction will be:

$\text{Rate of reaction}=-\frac{1}{5}\frac{d[Br^-]}{dt}=-\frac{d[BrO_3^-]}{dt}=-\frac{1}{6}\frac{d[H^+]}{dt}=+\frac{1}{3}\frac{d[Br_2]}{dt}=+\frac{1}{3}\frac{d[H_2O]}{dt}$

Part (a) :

Given:

$\frac{1}{5}\frac{d[Br^-]}{dt}=1.56\times 10^{-4}M/s$

As,

$-\frac{1}{5}\frac{d[Br^-]}{dt}=+\frac{1}{3}\frac{d[Br_2]}{dt}$

and,

$\frac{d[Br_2]}{dt}=\frac{3}{5}\frac{d[Br^-]}{dt}$

$\frac{d[Br_2]}{dt}=\frac{3}{5}\times 1.56\times 10^{-4}M/s$

$\frac{d[Br_2]}{dt}=9.36\times 10^{-5}M/s$

Part (b) :

Given:

$\frac{1}{5}\frac{d[Br^-]}{dt}=1.56\times 10^{-4}M/s$

As,

$-\frac{1}{5}\frac{d[Br^-]}{dt}=-\frac{1}{6}\frac{d[H^+]}{dt}$

and,

$-\frac{1}{6}\frac{d[H^+]}{dt}=\frac{3}{5}\frac{d[Br^-]}{dt}$

$\frac{d[H^+]}{dt}=\frac{6}{5}\times 1.56\times 10^{-4}M/s$

$\frac{d[H^+]}{dt}=1.87\times 10^{-4}M/s$

5 0

3 years ago

How much energy does it take to melt 2 kg of ice? (Refer to table of constants for water.)

ioda

It would be C

2 kg x 1000 g/kg x 1mol/18.02 x 6.03 kj/mol = 669kj

5 0

2 years ago

Read 2 more answers

The following do not represent valid ground-state electron configurations for an atom either because they violate the Pauli excl

svetoff [14.1K]

Answer:

For both cases the answer is C

Explanation:

We can see that the orbitals are not filled in the order of increasing energy and the Pauli exclusion principle is violated because it does not follow the correct order of the electron configuration; In the first exercise after the 2s2 orbital, the 2p2 orbital follows.

For the second exercise, you must start in order with level 1 and correctly filling each of the sublevels corresponding to each level until reaching level 7 and thus completing the desired number of electrons.

7 0

2 years ago

Read 2 more answers

Amino acids are the building blocks of proteins. The simplest amino acid is glycine . Draw a Lewis structure for glycine. (Hint:

madam [21]

Answer:

Sorry for the lack of precision, if you have any questions you can consult me again.

Explanation:

Glycine is an amino acid, forms proteins and is also called in its molecular chemical formula as C2H5NO2

5 0

3 years ago