Answer: 2 V + 5 F2 > 2 V+5 + 10 F-
Explanation: First balance the chemical eq.
V + F2 > V+5 + 2F-
Second: Identify which is oxidised and reduced.
Oxidation: increase in oxidation #
Reduction : decrease in oxidation #
Third do half-reaction
Ox. V > V5+
Red. F2. > 2F-
Next add electrons to each positive sides of the reaction
Ox. V > V5+ + 5e-
Red. F2 + 2e- > 2F-
To make the number of electrons equal we will multiply the ox. side by 2 and reduction side by 5
2 ( V > V5+ + 5e-)
5 ( F2 + 2e- > 2F-)
The result will be:
2V + 5F2 + 10e > 2V5+ + 10e + 10 F-
Cancel the 10e in both sides.
Then the result will have equal charges in the reactant and product side
