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Yuliya22 [10]
3 years ago
7

The bonds of oxygen molecules are broken by sunlight. The minimum energy required to break the oxygen-oxygen bond is 495 kJ/mol

O2. What wavelength of sunlight is required to break the bond in one O2 molecule?
Chemistry
1 answer:
olga_2 [115]3 years ago
4 0

Answer:

The wavelength of sunlight is required to break the bond in one oxygen molecule is 242 nm.

Explanation:

Energy required to break the 1 mol oxygen-oxygen bond:

=495 kJ=495000J

1 mol = 6.022\times 10^{23} molecules

Energy required to break 1 molecule of oxygen molecule= E

= E=\frac{495000 J}{6.022\times 10^{23}}=8.219\times 10^{-19} J

The energy required to break the  1 molecule of oxygen is equal to enrgy of one photon of a sunlight.

E=\frac{h\times c}{\lambda}

where,

\lambda = wavelength of the light

E = energy of the photon

h = Planck's constant = 6.63\times 10^{-34}Js

c = speed of light = 3\times 10^8m/s

\lambda=\frac{h\times c}{E}

\lambda =\frac{6.63\times 10^{-34}Js \times 3\times 10^8m/s}{8.219\times 10^{-19} J}=2.42\times 10^{-7} m=242 nm

The wavelength of sunlight is required to break the bond in one oxygen molecule is 242 nm.

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The isotope that is more abundant, given the data is isotope Li7

<h3>Assumption</h3>
  • Let Li6 be isotope A
  • Let Li7 be isotope B

<h3>How to determine whiche isotope is more abundant</h3>
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  • Molar mass of isotope B (Li7) = 7.02 u
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Atomic mass = [(mass of A × A%) / 100] + [(mass of B × B%) / 100]

6.94 = [(6.02 × A%) / 100] + [(7.02 × (100 - A)) / 100]

6.94 = [6.02A% / 100] + [702 - 7.02A% / 100]

6.94 = [6.02A% + 702 - 7.02A%] / 100

Cross multiply

6.02A% + 702 - 7.02A% = 6.94 × 100

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Collect like terms

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Thus,

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Abundance of B = 92%

SUMMARY

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brainly.com/question/24311846

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