1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Yuliya22 [10]
3 years ago
7

The bonds of oxygen molecules are broken by sunlight. The minimum energy required to break the oxygen-oxygen bond is 495 kJ/mol

O2. What wavelength of sunlight is required to break the bond in one O2 molecule?
Chemistry
1 answer:
olga_2 [115]3 years ago
4 0

Answer:

The wavelength of sunlight is required to break the bond in one oxygen molecule is 242 nm.

Explanation:

Energy required to break the 1 mol oxygen-oxygen bond:

=495 kJ=495000J

1 mol = 6.022\times 10^{23} molecules

Energy required to break 1 molecule of oxygen molecule= E

= E=\frac{495000 J}{6.022\times 10^{23}}=8.219\times 10^{-19} J

The energy required to break the  1 molecule of oxygen is equal to enrgy of one photon of a sunlight.

E=\frac{h\times c}{\lambda}

where,

\lambda = wavelength of the light

E = energy of the photon

h = Planck's constant = 6.63\times 10^{-34}Js

c = speed of light = 3\times 10^8m/s

\lambda=\frac{h\times c}{E}

\lambda =\frac{6.63\times 10^{-34}Js \times 3\times 10^8m/s}{8.219\times 10^{-19} J}=2.42\times 10^{-7} m=242 nm

The wavelength of sunlight is required to break the bond in one oxygen molecule is 242 nm.

You might be interested in
Oxygen gas can be prepared by heating potassium chlorate according to the following equation: 2KClO3(s)2KCl(s) + 3O2(g) The prod
Ipatiy [6.2K]

Answer:

The number of moles of KClO₃ reacted was 0,15 mol

Explanation:

For the reaction:

2KClO₃(s) → 2KCl(s) + 2O₂(g)

The only gas product is O₂.

Total pressure is the sum of vapor pressure of water with O₂ gas formed. Thus, pressure of O₂ is:

749mmHg - 23,8mmHg = 725,2mmHg

Using gas law:

PV/RT = n

Where:

P is pressure (725,2mmHg ≡ <em>0,9542atm</em>)

V is volume (<em>5,76L</em>)

R is gas constant (<em>0,082 atmL/molK</em>)

And T is temperature (25°C ≡ <em>298,15K</em>)

Replacing, number of moles of O₂ are <em>0,2248 moles</em>

As 2 moles of KClO₃ react with 3 moles of O₂ the moles of KClO₃ that reacted was:

0,2248 mol O₂×\frac{2 mol KClO_{3}}{3 mol O_{2}} = <em>0,15 mol of KClO₃</em>

I hope it helps!

8 0
4 years ago
A student wants to form 2‑hexanol using acidic hydration. He finds four alkenes in the inventory cabinet that could be possible
julia-pushkina [17]

Answer:

Look on the picture.

Explanation:

He could find only 2 isomers of n-hexane alkenes for this reaction. Other two could be marked from other direction.

8 0
4 years ago
The lewis dot notation for two atoms is shown. What is represented by this notation? K loses one portion to CI, K gains one port
telo118 [61]

Answer:

K loses one electron to CI

Explanation:

The lewis electron dot notation shows only the chemical symbol of the element surrounded by dots to represent the valence electrons.

  We have atom of K with one valence electrons

   Cl with 7 valence electrons

For an electrostatic attraction to occur, both particles must be charged. To do this, one of the species must lose an electron, and the other gains it.

This will make both species attain a stable octet;

   Hence, K will lose 1 electron and Cl will gain the electrons.

6 0
3 years ago
In which substance does chlorine have an oxidation number of +1?
Anton [14]
The answer is (3) HClO. In the Cl2, chlorine has an oxidation number of zero. In HCl, the oxidation number is -1. In HClO2, the oxidation number is +3. In HClO, it is +1. You can calculate this by using O with oxidation number of -2 and H with +1.
8 0
3 years ago
5. A beam of photons with a minimum energy of 222 kJ/mol can eject electrons from a potassium surface. Estimate the range of wav
torisob [31]

Answer: The range of wavelengths of light that can be used to cause given phenomenon is 8.953 \times 10^{21} m.

Explanation:

Given: 222 kJ/mol (1 kJ = 1000 J) = 222000 J

Formula used is as follows.

E = \frac{hc}{\lambda}

where,

E = energy

h = Planck's constant = 6.625 \times 10^{-25} Js

c = speed of light = 3 \times 10^{8} m/s

Substitute the values into above formula as follows.

E = \frac{hc}{\lambda}\\222000 J = \frac{6.625  \times 10^{-34}Js \times 3 \times 10^{8} m/s}{\lambda}\\\lambda = 8.953 \times 10^{21} m

Thus, we can conclude that the range of wavelengths of light that can be used to cause given phenomenon is 8.953 \times 10^{21} m.

7 0
3 years ago
Other questions:
  • Consider the following thermochemical equations.
    7·1 answer
  • 3. Construct Explanations Pangaea was not
    10·1 answer
  • Cu+2AgNO
    9·1 answer
  • To cool foods quickly, place them
    14·1 answer
  • Given the name of a binary molecular compound, describe how to write its formula. Use dinitrogen trioxide as an example.
    5·2 answers
  • “Jesus came to serve. How is He calling me to serve?”
    8·1 answer
  • 175 pounds convert to kilograms
    11·2 answers
  • What Makes You Unique??<br> Just bored so yea :))) Free 15 points :)
    12·2 answers
  • If 10ml of 1.00M HCI(aq) neutralized 30 ml of an NaOH solution. What was the molarity of the Na OH solution?​
    7·2 answers
  • Determine the empirical formula. a 3.880g sample contains 0.691g of magnesium , 1.84 g of sulfur , and 1.365 g of oxygen .
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!