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Yuliya22 [10]
3 years ago
7

The bonds of oxygen molecules are broken by sunlight. The minimum energy required to break the oxygen-oxygen bond is 495 kJ/mol

O2. What wavelength of sunlight is required to break the bond in one O2 molecule?
Chemistry
1 answer:
olga_2 [115]3 years ago
4 0

Answer:

The wavelength of sunlight is required to break the bond in one oxygen molecule is 242 nm.

Explanation:

Energy required to break the 1 mol oxygen-oxygen bond:

=495 kJ=495000J

1 mol = 6.022\times 10^{23} molecules

Energy required to break 1 molecule of oxygen molecule= E

= E=\frac{495000 J}{6.022\times 10^{23}}=8.219\times 10^{-19} J

The energy required to break the  1 molecule of oxygen is equal to enrgy of one photon of a sunlight.

E=\frac{h\times c}{\lambda}

where,

\lambda = wavelength of the light

E = energy of the photon

h = Planck's constant = 6.63\times 10^{-34}Js

c = speed of light = 3\times 10^8m/s

\lambda=\frac{h\times c}{E}

\lambda =\frac{6.63\times 10^{-34}Js \times 3\times 10^8m/s}{8.219\times 10^{-19} J}=2.42\times 10^{-7} m=242 nm

The wavelength of sunlight is required to break the bond in one oxygen molecule is 242 nm.

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Answer:

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Explanation:

Step 1: Data given

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Total pressure = 120 psi

Temperature = 26°C

molar mass of air = 28.8 g/mol

Step 2:  Convert psi to atm

(

120 psi) (1 atm / 14.7 psi) = 8.163

Step 4: Calculate moles

PV = nRT

 ⇒ with P = the pressure = 8.163 atm

⇒ with V = the volume = 860 mL = 0.860 L

⇒ with n = the number of moles = TO BE DETERMINED

⇒ with R = the universal gas constant = 0.08206 L*atm/K*mol

⇒ with T = the temperature = 26 °C = 299 Kelvin

n = (8163*0.860)/(0.08206*299)

n = 0.2861 moles of gas

Step 5: Calculate the mass of air in an air-filled tire.

Mass = moles * molar mass

Mass = (0.2861 moles of gas) (28.8 g/mol)  

Mass = 8.24 grams

Step 6: Calculate the mass of helium in a helium- filled tire.

mass of helium = 0.2861 moles of gas * 4 g/mol)  

mass of helium  = 1.14 grams

Step 7: What is the mass difference between the two?

Δmass=  8.24 grams -  1.14 grams

Δmass= 7.10 grams

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Answer:

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Explanation:

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