Answer:
C4H8O4
Explanation:
Let (CH20)x
C=1*12.01=12.01 (12.01, 1.01, 16.00 Avg mass of elements)
H=2*1.01=2.01
O=1*16.00=16.00
12.01 + 2.01 + 16.00 = 30.03
120.12/30,03=4
==> (CH2O)4 = C4H8O4
The average sedentary male will achieve a VO2 max of approximately 35 to 40 mL/Kg/min. And the average sedentary female will score a VO2 max of between 27 an 30 mL/Kg/min.
Since the sample size is below 30, in this case we use
the t statistic. The formula for t score is:
t = (x – u) / (σ / sqrt n)
where,
x = the level l = unknown
u = sample mean = 120 mg / dl
σ = standard deviation = 20 mg / dl
n = sample size or number of results = 5
Using the standard distribution tables for t, we can find
the value of t given the probability (P = 0.15) and degrees of freedom (DOF).
t = 1.036
Going back to the
formula for t score:
1.036 = (x – 120)
/ (20 / sqrt 5)
x = 129.27 mg /
dl = l
First, in this case, we define the K constant as the solubility of the solute in water divided by the solubility of the solute in ether.
K = (X grams of solute / 75 mL of ethyl ether) / (5 g of solute / 100 mL of water)
K = (X / 75) / (5 / 100)
1 = (X / 75) / (5 / 100)
5 / 100 = X / 75
0,05 = X /75
X = 0,05 × 75 = 3.75 g of solute that will be extracted by the ether
Answer:
Explanation:
In an acid-catalyzed epoxide ring-opening reaction, there is a formation of two intermediate in the reaction. The first stage involves the protonation of oxygen in the epoxide. The stage is followed by the attraction of water molecules onto the more substituted carbon atom in the epoxide ring. The stepwise reaction mechanism can be seen in the image attached below.