In a fully inflated basketball, there are more particles of gas.
Answer: Option D.
<u>Explanation:</u>
When a ball is fully inflated, it means it has a lot of air in it. With a lot of air in it, it means that there a lot of gas particles in that ball. With the large amount of gas particles in it, there is a lot of collision among these particles inside the ball.
This collision leads to the pressure on the greater side compared to the ball which has less air in it and is deflated because it has less particles of gas inside.
Answer:
Explanation:
Similarities.
Both Ionic and covalents bond produce exothermic reactions.
They are both neutral.in Ionic bonds, the two opposite charge will terminate each other and in covalent, the neutral molecules tend to share electrons.
Difference
Ionic bonds have high polarity while covalent have low.
Ionic bonds have no definite shape, covalent have.
Ionic have high melting points, covalent have low.
Io ic have high boiling point, covalents have low.
Sodium chloride, methane gas and water
Answer:
5.37 × 10⁻⁴ mol/L
Explanation:
<em>A chemist makes 660. mL of magnesium fluoride working solution by adding distilled water to 230. mL of a 0.00154 mol/L stock solution of magnesium fluoride in water. Calculate the concentration of the chemist's working solution. Round your answer to 3 significant digits.</em>
Step 1: Given data
- Initial concentration (C₁): 0.00154 mol/L
- Initial volume (V₁): 230. mL
- Final concentration (C₂): ?
- Final volume (V₂): 660. mL
Step 2: Calculate the concentration of the final solution
We want to prepare a dilute solution from a concentrated one. We can calculate the concentration of the final solution using the dilution rule.
C₁ × V₁ = C₂ × V₂
C₂ = C₁ × V₁ / V₂
C₂ = 0.00154 mol/L × 230. mL / 660. mL = 5.37 × 10⁻⁴ mol/L
Conductivity is a measurement of the ability of an aqueous solution to transfer an electrical current.
Explanation:
To calculate the conductivity of a solution you simply multiply the concentration of each ion in solution by its molar conductivity and charge then add these values for all ions in solution.
