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d1i1m1o1n [39]
3 years ago
14

A given atom has 3 protons, 4 neutrons, and 3 electrons. Describe how you can use those three values to describe the structure,

charge, and mass of the atom.
Chemistry
1 answer:
ELEN [110]3 years ago
3 0
Charge # = protons - electons 

Mass # = protons + neutrons 

so that would be 

3-3= charge#
3+4= mass#
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When 20 calories of heat is added to 2.0 grams of water at 15 c, the temperature of the water increases to?
Hoochie [10]
20 calories equals to 8.368 joules.
4.184 J is needed to raise 1 gram of water.(Heat capacity of water)
for 2 grams of water 8.368 joules.

So the answer is 16 c.
8 0
3 years ago
What is the percent composition of YAG (Yttrium Aluminum Garnet). The formula for
andre [41]

Answer:   Y  21.38 % , Al  32.44 % and O 46.16 %

Explanation: Molar mass of YAl5O12 is 88.91 + 5·26.98+12·16

= 415.81 g/mol

  m-% ( Y) = 88.91 / 415.81 = 21.38 % ,     m-% (Al) = 5·26.98 / 415.81 =

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3 0
3 years ago
Please help
Sonbull [250]

Answer:

A is the answer.

Explanation:

4 0
3 years ago
Read 2 more answers
A certain liquid X has a normal freezing point of 7.60 °C and a freezing point depression constant K= 6.90 °C-kg-mol. Calculate
Dmitry [639]

<u>Answer:</u> The freezing point of solution is -5.11°C

<u>Explanation:</u>

Vant hoff factor for ionic solute is the number of ions that are present in a solution. The equation for the ionization of sodium chloride follows:

NaCl(aq.)\rightarrow Na^{+}(aq.)+Cl^-(aq.)

The total number of ions present in the solution are 2.

To calculate the molality of solution, we use the equation:

Molality=\frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ in grams}}

Where,

m_{solute} = Given mass of solute (NaCl) = 7.57 g

M_{solute} = Molar mass of solute (NaCl) = 58.44 g/mol

W_{solvent} = Mass of solvent (liquid X) = 350.0 g

Putting values in above equation, we get:

\text{Molality of }NaCl=\frac{7.57\times 1000}{58.44\times 350.0}\\\\\text{Molality of }NaCl=0.370m

To calculate the depression in freezing point, we use the equation:

\Delta T=iK_fm

where,

i = Vant hoff factor = 2

K_f = molal freezing point depression constant = 6.90°C/m

m = molality of solution = 0.370 m

Putting values in above equation, we get:

\Delta T=2\times 6.90^oC/m.g\times 0.370m\\\\\Delta T=5.11^oC

Depression in freezing point is defined as the difference in the freezing point of water and freezing point of solution.

\Delta T=\text{freezing point of water}-\text{freezing point of solution}

\Delta T = 5.11 °C

Freezing point of water = 0°C

Freezing point of solution = ?

Putting values in above equation, we get:

5.106^oC=0^oC-\text{Freezing point of solution}\\\\\text{Freezing point of solution}=-5.11^oC

Hence, the freezing point of solution is -5.11°C

7 0
4 years ago
Which pair of elements show similarities in the pattern of chemical bonding?
tamaranim1 [39]
The answer is A, Lithium and Sodium.
3 0
4 years ago
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