Explanation:
As it is given that water level is same as outside which means that theoretically, P = 756.0 torr.
So, using ideal gas equation we will calculate the number of moles as follows.
PV = nRT
or, n =
=
= 0.0052 mol
Also, No. of moles =
0.0052 mol =
mass = 0.0104 g
As some of the water over which the hydrogen gas has been collected is present in the form of water vapor. Therefore, at
= 24 mm Hg
= atm
= 0.03158 atm
Now, P =
= 0.963 atm
Hence, n =
= 0.0056 mol
So, mass of = 0.0056 mol × 2
= 0.01013 g (actual yield)
Therefore, calculate the percentage yield as follows.
Percent yield =
=
= 97.49%
Thus, we can conclude that the percent yield of hydrogen for the given reaction is 97.49%.