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rosijanka [135]
3 years ago
9

How many grams of nitric acid are needed to produce 30.0 g of water?

Chemistry
1 answer:
shusha [124]3 years ago
7 0

Answer:

Mass = 32.13 g

Explanation:

Given data:

Mass of water produced = 30 g

Mass of nitric acid needed = ?

Solution:

Chemical equation:

4Zn + 10HNO₃  → 4Zn(NO₃)₂ + NH₄NO₃ + 3H₂O

Number of moles of water:

Number of  moles = mass/molar mass

Number of moles = 30 g/ 18 g/mol

Number of moles = 1.7 mol

Now we will compare the moles of water with nitric acid.

                               HNO₃          :            H₂O

                                   10             :             3

                                  1.7              :          3/10×1.7 = 0.51 mol

Mass of nitric acid:

Mass = number of moles × molar mass

Mass = 0.51 mol × 63.01 g/mol

Mass = 32.13 g

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Answer:

C_t=0.165M

Explanation:

From the question we are told that:

Slope K=0.056 M-1 s -1

initial Concentration C_1=2.2M

Time t=100

Generally the equation for Raw law is mathematically given by

\frac{1}{C}_t=kt+\frac{1}{C}_0

\frac{1}{C}_t=0.056*100+\frac{1}{2.2}_0

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3 years ago
is the atomic mass of chlorine represented by the mass of the most common naturally occurring isotope in chlorine?
IrinaVladis [17]
Combine the number of its Protons and Neutrons and you will have its atomic mass.
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3 years ago
How many moles of mercury, Hg, are there in 1.30 x 10^7 atoms of murcury? PLEASE HELP, IT'S URGENT! Thank you! (:
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1 mole Hg ---------------- 6.02x10²³ atoms
??  ------------------------- 1.30 x10⁷ atoms

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3 years ago
What is the stoichiometric coefficient for oxygen when the following equation is balanced using the lowest whole-number coeffici
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Answer:

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To know the coefficient of O2 in the above equation, let us balance the equation.

The above equation can be balance as follow:

C3H6O2(l) + O2(g) → CO2(g) + H2O(l)

There are 3 atoms of C on the left side and 1 atom on the right side. It can be balance by putting 3 in front of CO2 as shown below:

C3H6O2(l) + O2(g) → 3CO2(g) + H2O(l)

There are 6 atoms of H on the left side and 2 atoms on the right side. It can be balance by putting 3 in front of H2O as shown below:

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There are a total of 4 atoms of O on the left side and a total of 9 atoms on the right side. It can be balance by putting 7/2 in front of O2 as show below:

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Multiply through by 2

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Now, the equation is balanced.

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