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rosijanka [135]
3 years ago
9

How many grams of nitric acid are needed to produce 30.0 g of water?

Chemistry
1 answer:
shusha [124]3 years ago
7 0

Answer:

Mass = 32.13 g

Explanation:

Given data:

Mass of water produced = 30 g

Mass of nitric acid needed = ?

Solution:

Chemical equation:

4Zn + 10HNO₃  → 4Zn(NO₃)₂ + NH₄NO₃ + 3H₂O

Number of moles of water:

Number of  moles = mass/molar mass

Number of moles = 30 g/ 18 g/mol

Number of moles = 1.7 mol

Now we will compare the moles of water with nitric acid.

                               HNO₃          :            H₂O

                                   10             :             3

                                  1.7              :          3/10×1.7 = 0.51 mol

Mass of nitric acid:

Mass = number of moles × molar mass

Mass = 0.51 mol × 63.01 g/mol

Mass = 32.13 g

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2 years ago
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2 years ago
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Answer:

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molecules in 17.75 g of NaCl = 0.3034\times 6.023\times 10^{23}=1.827\times 10^{23}

formula units 17.75 g of NaCl = 0.3034\times 6.023\times 10^{23}=1.827\times 10^{23}

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