Answer:
i believe it would be 6 1/2 simplified or 6 2/4 unsimplified
Step-by-step explanation:
<h2>
Maximum area is 25 m²</h2>
Explanation:
Let L be the length and W be the width.
Aidan has 20 ft of fence with which to build a rectangular dog run.
Fencing = 2L + 2W = 20 ft
L + W = 10
W = 10 - L
We need to find what is the largest area that can be enclosed.
Area = Length x Width
A = LW
A = L x (10-L) = 10 L - L²
For maximum area differential is zero
So we have
dA = 0
10 - 2 L = 0
L = 5 m
W = 10 - 5 = 5 m
Area = 5 x 5 = 25 m²
Maximum area is 25 m²
Answer:
52
Step-by-step explanation:
2(4^2 + 10) =
We do what's in the parenthesis first.
4^2 = 16 and 16+10 =26.
2(26)
= 52
Answer:
0.9 , 0.088 , 0.032
Step-by-step explanation:
0.9 --> 1st greatest
0.088 --> 2nd greatest
0.032 --> 3rd greatest
So, 0.9 , 0.088 , 0.032
